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anonymous
 5 years ago
y''+4y=2sin(2t) y(0)=1 y'(0)=1solve the I.V.P. the complex root threw me. is it c1cos(2t) +c2sin(2t)?
anonymous
 5 years ago
y''+4y=2sin(2t) y(0)=1 y'(0)=1solve the I.V.P. the complex root threw me. is it c1cos(2t) +c2sin(2t)?

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0yes you are right so far

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k thanks, i messed up the math somewhere then ill have to redo it.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0that site is nice above

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok you know we only found the homogeneous solution right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i can do the rest i was just unsure about the complex root and setting up the homogeneous solution. i get y(t)=c1(2t) +c2sin(2t)(1/2)tcos(2t) for the gen solution. that seem right?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i assume you accidently left out the cos of that constant thingy i will check your solution in just a sec k?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok your solution is not checking out i tried it twice maybe a maybe a mistake but let me try actually getting the nonhomogeneous k? thats the only thats not working out right now

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the nonhomogeneous is y=sin(2t)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i think thats right its just weird to see the nonhomogeneous solution as a part of the homogenous solution

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0let me see what i come up with doing what you which i think you tried y=Atcos(2t) right?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i think i made a mistake in checking it because your solution is what i just found sorry

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0did you try checking it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha yes. i think its all set i went back over the work. man i miss diff eq. that class was interesting.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Refer to the attachment.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i'm confused why are you doing t's and x's?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well is my face red. Mortified. The second solution version is attached. Everything is in terms of the independent variable t now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Some of the more complex expressions could be further simplified.
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