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anonymous
 5 years ago
i'm hoping someone can help me with this problem..
A falling object encounters air resistance that is proportional to its velocity. The acceleration due to gravity is 9.8 m/s. The net change in velocity is dv/dt = kv  9.8
a. Find the velocity of the object as a function of time if the initial velocity is Vo
b. Use the result of part a to find the limit of the velocity as t approaches infinity
c. Integrate the velocity function found in part a to find the position function s.
anonymous
 5 years ago
i'm hoping someone can help me with this problem.. A falling object encounters air resistance that is proportional to its velocity. The acceleration due to gravity is 9.8 m/s. The net change in velocity is dv/dt = kv  9.8 a. Find the velocity of the object as a function of time if the initial velocity is Vo b. Use the result of part a to find the limit of the velocity as t approaches infinity c. Integrate the velocity function found in part a to find the position function s.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For a, if you integrate with respect to t you will get your velocity function v(t) = kvt  9.8t + Vo Because v(t) is a polynomial to take the limit as t approaches infinity just plug in infinity and use l'hopitals rule to evaluate since it is a indeterminate form c. \[1/2t^2(kv  9.8) + Vot + Xo\]
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