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dryicegrl

  • 3 years ago

The wind-chill index is modeled by the function below where T is the temperature (°C) and v is the wind speed (km/h). W = 13.12 + 0.6215T - 11.37v0.16 + 0.3965Tv0.16 When T = 13°C and v = 34 km/h, by how much would you expect the apparent temperature W to drop if the actual temperature decreases by 1°C? (Enter your answer to 1 decimal place.) °C What if the wind speed increases by 1 km/h?(Enter your answer to 2 decimal places.) °C

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  1. him1618
    • 3 years ago
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    is that v^0.16??

  2. dryicegrl
    • 3 years ago
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    yes

  3. him1618
    • 3 years ago
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    and is the apparent temp the wind chill W?

  4. dryicegrl
    • 3 years ago
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    yes

  5. dryicegrl
    • 3 years ago
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    I was think I would have to find W with respect of T first, but I am not sure where the less 1 degree comes in

  6. him1618
    • 3 years ago
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    differentiate wrt T dW/dT = 0.6215 + 0.3965 (v)^0.16 dW = [0.6215 + 0.3965 (v)^0.16] dT dT=1 hence find dW

  7. him1618
    • 3 years ago
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    got it??

  8. 3pwood
    • 3 years ago
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    Depening on what class this is for, you may be supposed to do this with partial derivatives, but you can actually just plug in the given T and v, and compute an initial W, then change the T or v by the one unit as requested to get a final W, then just subtract to find the difference between W values.

  9. him1618
    • 3 years ago
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    yeah hes right

  10. dryicegrl
    • 3 years ago
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    well yes i am suppose to use partial derivatives

  11. him1618
    • 3 years ago
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    then do as ive done....it should work...

  12. dryicegrl
    • 3 years ago
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    I am....what about the dT=1 part?

  13. him1618
    • 3 years ago
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    dT is the change in actual temp, which is given to be 1 degree,

  14. him1618
    • 3 years ago
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    got it?

  15. dryicegrl
    • 3 years ago
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    yes

  16. him1618
    • 3 years ago
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    ok....good luck fr the others

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