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dryicegrl
Group Title
The windchill index is modeled by the function below where T is the temperature (°C) and v is the wind speed (km/h).
W = 13.12 + 0.6215T  11.37v0.16 + 0.3965Tv0.16
When T = 13°C and v = 34 km/h, by how much would you expect the apparent temperature W to drop if the actual temperature decreases by 1°C? (Enter your answer to 1 decimal place.)
°C
What if the wind speed increases by 1 km/h?(Enter your answer to 2 decimal places.)
°C
 3 years ago
 3 years ago
dryicegrl Group Title
The windchill index is modeled by the function below where T is the temperature (°C) and v is the wind speed (km/h). W = 13.12 + 0.6215T  11.37v0.16 + 0.3965Tv0.16 When T = 13°C and v = 34 km/h, by how much would you expect the apparent temperature W to drop if the actual temperature decreases by 1°C? (Enter your answer to 1 decimal place.) °C What if the wind speed increases by 1 km/h?(Enter your answer to 2 decimal places.) °C
 3 years ago
 3 years ago

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him1618 Group TitleBest ResponseYou've already chosen the best response.1
is that v^0.16??
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
and is the apparent temp the wind chill W?
 3 years ago

dryicegrl Group TitleBest ResponseYou've already chosen the best response.0
I was think I would have to find W with respect of T first, but I am not sure where the less 1 degree comes in
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
differentiate wrt T dW/dT = 0.6215 + 0.3965 (v)^0.16 dW = [0.6215 + 0.3965 (v)^0.16] dT dT=1 hence find dW
 3 years ago

3pwood Group TitleBest ResponseYou've already chosen the best response.0
Depening on what class this is for, you may be supposed to do this with partial derivatives, but you can actually just plug in the given T and v, and compute an initial W, then change the T or v by the one unit as requested to get a final W, then just subtract to find the difference between W values.
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
yeah hes right
 3 years ago

dryicegrl Group TitleBest ResponseYou've already chosen the best response.0
well yes i am suppose to use partial derivatives
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
then do as ive done....it should work...
 3 years ago

dryicegrl Group TitleBest ResponseYou've already chosen the best response.0
I am....what about the dT=1 part?
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
dT is the change in actual temp, which is given to be 1 degree,
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.1
ok....good luck fr the others
 3 years ago
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