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Use the general formula to write the area A of the enclosure as a function of w (that is, only the variable w should appear in the function). it should be a quadratic function

Mathematics
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What enclosure?
what is the enclosure? are we enclosing a rectangle or something? or can we enclose whatever we want?
hold on im trying to get the file of the actuall question its part of a project

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Other answers:

Its to question number 5
I am completely lost
maybe this will help
1 Attachment
Okay, so you have 682 feet of fencing to make up two "width sides" and one "length side" this translates to the equation: 682 = 2W + L You know from basic geometry that the area of a rectangle is length times width: A = L*W What you need to do is solve the first equation for L in terms of W: 682 = 2W + L L = 682 -2W Then substitute that L value into the second function so that you have A in terms of just W: A = L*W A = (682 -2W)W
anyone?
?
anyone what?
the site froze on me im taking a look at it now
ok lol
now if i can get the window correct on my ti 84 :P
any help with that?
go to Y=
type 682x-2x^2
then go to window
yeah i got the equation in its just getting a clear shot of the parabola
go to where it says x min and type 100 go to where it says x max and type 200 go to where it says y min and type 80 go to where it says y max and type 60000 and see if it looks viewable
try going to the highest point on the curve and approximate what it is
it works but im going to need both sides of the parabola can i just extend the xmin
holy crap I got it
no you are fine but you can if you want to
you are amazing!
did you use the maximum feature on your calculator?
ximn -100 xmax 400 ymin 80 ymax 60000
no thats not what i meant
do you see calc?
i havent taken advantage of that yet
lets do it
i got the max
do you see maximum
yeah did the whole left and right bound
thats going to give me the best area correct?
oh nice i got (170.50001,58140.5) this is just an appoximation I arleady found the exact on that pdf file
your approximation doesn't have to be mine but both of ours should be pretty close to the same thing is yours close to my?
its exact
k now you remember the file i gave you right? that vertex of the parabola i found by putting the parabola in vertex form gave me the exact (max width,max area)
what file
scroll up if you haven't seen the file and click on it
looking at it now
you remember when you uploaded a file i uploaded a file like a few minutes afterwards
yeah i see it
if i have any more questions ill post them
ok make a new post though because i'm about to leave or do it so you can get someone's attention and bring them back here to help k?
or 3wood might come back
gn guys and peace
thanks for all the help both of you are life savers

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