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riyor

  • 3 years ago

Use the general formula to write the area A of the enclosure as a function of w (that is, only the variable w should appear in the function). it should be a quadratic function

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  1. 3pwood
    • 3 years ago
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    What enclosure?

  2. myininaya
    • 3 years ago
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    what is the enclosure? are we enclosing a rectangle or something? or can we enclose whatever we want?

  3. riyor
    • 3 years ago
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    hold on im trying to get the file of the actuall question its part of a project

  4. riyor
    • 3 years ago
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    Its to question number 5

  5. riyor
    • 3 years ago
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    I am completely lost

  6. myininaya
    • 3 years ago
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    maybe this will help

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  7. 3pwood
    • 3 years ago
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    Okay, so you have 682 feet of fencing to make up two "width sides" and one "length side" this translates to the equation: 682 = 2W + L You know from basic geometry that the area of a rectangle is length times width: A = L*W What you need to do is solve the first equation for L in terms of W: 682 = 2W + L L = 682 -2W Then substitute that L value into the second function so that you have A in terms of just W: A = L*W A = (682 -2W)W

  8. riyor
    • 3 years ago
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    anyone?

  9. myininaya
    • 3 years ago
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    ?

  10. myininaya
    • 3 years ago
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    anyone what?

  11. riyor
    • 3 years ago
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    the site froze on me im taking a look at it now

  12. myininaya
    • 3 years ago
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    ok lol

  13. riyor
    • 3 years ago
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    now if i can get the window correct on my ti 84 :P

  14. riyor
    • 3 years ago
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    any help with that?

  15. myininaya
    • 3 years ago
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    go to Y=

  16. myininaya
    • 3 years ago
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    type 682x-2x^2

  17. myininaya
    • 3 years ago
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    then go to window

  18. riyor
    • 3 years ago
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    yeah i got the equation in its just getting a clear shot of the parabola

  19. myininaya
    • 3 years ago
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    go to where it says x min and type 100 go to where it says x max and type 200 go to where it says y min and type 80 go to where it says y max and type 60000 and see if it looks viewable

  20. myininaya
    • 3 years ago
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    try going to the highest point on the curve and approximate what it is

  21. riyor
    • 3 years ago
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    it works but im going to need both sides of the parabola can i just extend the xmin

  22. riyor
    • 3 years ago
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    holy crap I got it

  23. myininaya
    • 3 years ago
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    no you are fine but you can if you want to

  24. riyor
    • 3 years ago
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    you are amazing!

  25. myininaya
    • 3 years ago
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    did you use the maximum feature on your calculator?

  26. riyor
    • 3 years ago
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    ximn -100 xmax 400 ymin 80 ymax 60000

  27. myininaya
    • 3 years ago
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    no thats not what i meant

  28. myininaya
    • 3 years ago
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    do you see calc?

  29. riyor
    • 3 years ago
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    i havent taken advantage of that yet

  30. myininaya
    • 3 years ago
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    lets do it

  31. riyor
    • 3 years ago
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    i got the max

  32. myininaya
    • 3 years ago
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    do you see maximum

  33. riyor
    • 3 years ago
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    yeah did the whole left and right bound

  34. riyor
    • 3 years ago
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    thats going to give me the best area correct?

  35. myininaya
    • 3 years ago
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    oh nice i got (170.50001,58140.5) this is just an appoximation I arleady found the exact on that pdf file

  36. myininaya
    • 3 years ago
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    your approximation doesn't have to be mine but both of ours should be pretty close to the same thing is yours close to my?

  37. riyor
    • 3 years ago
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    its exact

  38. myininaya
    • 3 years ago
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    k now you remember the file i gave you right? that vertex of the parabola i found by putting the parabola in vertex form gave me the exact (max width,max area)

  39. riyor
    • 3 years ago
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    what file

  40. myininaya
    • 3 years ago
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    scroll up if you haven't seen the file and click on it

  41. riyor
    • 3 years ago
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    looking at it now

  42. myininaya
    • 3 years ago
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    you remember when you uploaded a file i uploaded a file like a few minutes afterwards

  43. riyor
    • 3 years ago
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    yeah i see it

  44. riyor
    • 3 years ago
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    if i have any more questions ill post them

  45. myininaya
    • 3 years ago
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    ok make a new post though because i'm about to leave or do it so you can get someone's attention and bring them back here to help k?

  46. myininaya
    • 3 years ago
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    or 3wood might come back

  47. myininaya
    • 3 years ago
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    gn guys and peace

  48. riyor
    • 3 years ago
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    thanks for all the help both of you are life savers

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