riyor
Use the general formula to write the area A of the enclosure as a function of w (that is, only
the variable w should appear in the function). it should be a quadratic function
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3pwood
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What enclosure?
myininaya
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what is the enclosure?
are we enclosing a rectangle or something?
or can we enclose whatever we want?
riyor
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hold on im trying to get the file of the actuall question its part of a project
riyor
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Its to question number 5
riyor
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I am completely lost
myininaya
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maybe this will help
3pwood
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Okay, so you have 682 feet of fencing to make up two "width sides" and one "length side" this translates to the equation:
682 = 2W + L
You know from basic geometry that the area of a rectangle is length times width:
A = L*W
What you need to do is solve the first equation for L in terms of W:
682 = 2W + L
L = 682 -2W
Then substitute that L value into the second function so that you have A in terms of just W:
A = L*W
A = (682 -2W)W
riyor
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anyone?
myininaya
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?
myininaya
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anyone what?
riyor
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the site froze on me im taking a look at it now
myininaya
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ok lol
riyor
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now if i can get the window correct on my ti 84 :P
riyor
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any help with that?
myininaya
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go to Y=
myininaya
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type 682x-2x^2
myininaya
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then go to window
riyor
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yeah i got the equation in its just getting a clear shot of the parabola
myininaya
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go to where it says x min and type 100
go to where it says x max and type 200
go to where it says y min and type 80
go to where it says y max and type 60000
and see if it looks viewable
myininaya
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try going to the highest point on the curve and approximate what it is
riyor
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it works but im going to need both sides of the parabola
can i just extend the xmin
riyor
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holy crap I got it
myininaya
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no you are fine but you can if you want to
riyor
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you are amazing!
myininaya
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did you use the maximum feature on your calculator?
riyor
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ximn -100
xmax 400
ymin 80
ymax 60000
myininaya
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no thats not what i meant
myininaya
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do you see calc?
riyor
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i havent taken advantage of that yet
myininaya
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lets do it
riyor
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i got the max
myininaya
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do you see maximum
riyor
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yeah did the whole left and right bound
riyor
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thats going to give me the best area correct?
myininaya
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oh nice
i got (170.50001,58140.5)
this is just an appoximation
I arleady found the exact on that pdf file
myininaya
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your approximation doesn't have to be mine
but both of ours should be pretty close to the same thing
is yours close to my?
riyor
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its exact
myininaya
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k now you remember the file i gave you right?
that vertex of the parabola i found by putting the parabola in vertex form gave me the exact (max width,max area)
riyor
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what file
myininaya
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scroll up if you haven't seen the file and click on it
riyor
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looking at it now
myininaya
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you remember when you uploaded a file
i uploaded a file like a few minutes afterwards
riyor
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yeah i see it
riyor
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if i have any more questions ill post them
myininaya
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ok make a new post though because i'm about to leave or do it so you can get someone's attention and bring them back here to help k?
myininaya
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or 3wood might come back
myininaya
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gn guys and peace
riyor
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thanks for all the help both of you are life savers