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anonymous
 5 years ago
Use the general formula to write the area A of the enclosure as a function of w (that is, only
the variable w should appear in the function). it should be a quadratic function
anonymous
 5 years ago
Use the general formula to write the area A of the enclosure as a function of w (that is, only the variable w should appear in the function). it should be a quadratic function

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0what is the enclosure? are we enclosing a rectangle or something? or can we enclose whatever we want?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold on im trying to get the file of the actuall question its part of a project

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its to question number 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, so you have 682 feet of fencing to make up two "width sides" and one "length side" this translates to the equation: 682 = 2W + L You know from basic geometry that the area of a rectangle is length times width: A = L*W What you need to do is solve the first equation for L in terms of W: 682 = 2W + L L = 682 2W Then substitute that L value into the second function so that you have A in terms of just W: A = L*W A = (682 2W)W

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the site froze on me im taking a look at it now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now if i can get the window correct on my ti 84 :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i got the equation in its just getting a clear shot of the parabola

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0go to where it says x min and type 100 go to where it says x max and type 200 go to where it says y min and type 80 go to where it says y max and type 60000 and see if it looks viewable

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0try going to the highest point on the curve and approximate what it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it works but im going to need both sides of the parabola can i just extend the xmin

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no you are fine but you can if you want to

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0did you use the maximum feature on your calculator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ximn 100 xmax 400 ymin 80 ymax 60000

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no thats not what i meant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i havent taken advantage of that yet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah did the whole left and right bound

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats going to give me the best area correct?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oh nice i got (170.50001,58140.5) this is just an appoximation I arleady found the exact on that pdf file

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0your approximation doesn't have to be mine but both of ours should be pretty close to the same thing is yours close to my?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0k now you remember the file i gave you right? that vertex of the parabola i found by putting the parabola in vertex form gave me the exact (max width,max area)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0scroll up if you haven't seen the file and click on it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you remember when you uploaded a file i uploaded a file like a few minutes afterwards

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i have any more questions ill post them

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok make a new post though because i'm about to leave or do it so you can get someone's attention and bring them back here to help k?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0or 3wood might come back

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks for all the help both of you are life savers
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