What are the retricemptotes of the hyperbola: (x-1)^(2)/(25)-(y-4)^(2)/(16)=1

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What are the retricemptotes of the hyperbola: (x-1)^(2)/(25)-(y-4)^(2)/(16)=1

Mathematics
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bx/a where b and a are the sqruare roots of your denoms
since the x spot is bigger; that isthe width of the rectangular asymptotes of the hyperbola
-5,5 the height of this rectangular thing is -4,4

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Other answers:

i just noticed its off centered lol
(x-1)^2 (y-4)^2 -------- - ------- = 1 a^2=25 b^2=16 if this thing were centered wed have the rectangle asymptote at: y = (4/5) x but lets put it back now
(y-4) = (4/5)(x-1) y = (4/5)x - 4/5+20/5 y = (4/5)x + 16/5
and the other is just the negative slope of that i believe
so is (4/5)x+16/5 the retricepmtote?
if i did it right, it should be one of them; th eother would be: y = -(4/5)x + 16/5
y = (b/a)x is the normal asymptote; but since this is off centered, we gotta adjust for that discrepency
gotta get to calc class and learn limits lol.... have fun ;)
it can have multiple retricepmtotes, so would it be wrriten as (4/5)x, and 16/5?

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