anonymous
  • anonymous
What are the retricemptotes of the hyperbola: (x-1)^(2)/(25)-(y-4)^(2)/(16)=1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
bx/a where b and a are the sqruare roots of your denoms
amistre64
  • amistre64
since the x spot is bigger; that isthe width of the rectangular asymptotes of the hyperbola
amistre64
  • amistre64
-5,5 the height of this rectangular thing is -4,4

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amistre64
  • amistre64
i just noticed its off centered lol
amistre64
  • amistre64
(x-1)^2 (y-4)^2 -------- - ------- = 1 a^2=25 b^2=16 if this thing were centered wed have the rectangle asymptote at: y = (4/5) x but lets put it back now
amistre64
  • amistre64
(y-4) = (4/5)(x-1) y = (4/5)x - 4/5+20/5 y = (4/5)x + 16/5
amistre64
  • amistre64
and the other is just the negative slope of that i believe
anonymous
  • anonymous
so is (4/5)x+16/5 the retricepmtote?
amistre64
  • amistre64
if i did it right, it should be one of them; th eother would be: y = -(4/5)x + 16/5
amistre64
  • amistre64
y = (b/a)x is the normal asymptote; but since this is off centered, we gotta adjust for that discrepency
amistre64
  • amistre64
gotta get to calc class and learn limits lol.... have fun ;)
anonymous
  • anonymous
it can have multiple retricepmtotes, so would it be wrriten as (4/5)x, and 16/5?

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