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anonymous
 5 years ago
What are the retricemptotes of the hyperbola:
(x1)^(2)/(25)(y4)^(2)/(16)=1
anonymous
 5 years ago
What are the retricemptotes of the hyperbola: (x1)^(2)/(25)(y4)^(2)/(16)=1

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0bx/a where b and a are the sqruare roots of your denoms

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since the x spot is bigger; that isthe width of the rectangular asymptotes of the hyperbola

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05,5 the height of this rectangular thing is 4,4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i just noticed its off centered lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x1)^2 (y4)^2    = 1 a^2=25 b^2=16 if this thing were centered wed have the rectangle asymptote at: y = (4/5) x but lets put it back now

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(y4) = (4/5)(x1) y = (4/5)x  4/5+20/5 y = (4/5)x + 16/5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and the other is just the negative slope of that i believe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so is (4/5)x+16/5 the retricepmtote?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if i did it right, it should be one of them; th eother would be: y = (4/5)x + 16/5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = (b/a)x is the normal asymptote; but since this is off centered, we gotta adjust for that discrepency

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gotta get to calc class and learn limits lol.... have fun ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it can have multiple retricepmtotes, so would it be wrriten as (4/5)x, and 16/5?
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