f(x)=x^2- x- 2 What is the axis symmetry? The Ordered pair for vertex is ?

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f(x)=x^2- x- 2 What is the axis symmetry? The Ordered pair for vertex is ?

Mathematics
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the axis o' symmetry is: (-) middle# ------------- 2(first#)
-(-1) ----- = 1/2 2(1)
? that makes no sense the axis is a single number and vertex is set of two ordered numbers? Im confused

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the axis is; x=1/2
the vertex coords are what ever the function equals when x=1/2
so u mean .5?
or .05
1 -- = .5 2
ok ok then I just input that into the x variable to calculate the vertex order?
yes; your vertex sits at (.5,f(.5)) so whatever the equation equals at x=.5 is gonna be your y value for your vertex coords
the axis of symmetry is x = .5 right?
yes ok i get it now
i knew you would ;)
:) Thank You

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