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anonymous
 5 years ago
Can any1 explain the 3 theorems of differentiation?? pls pls
anonymous
 5 years ago
Can any1 explain the 3 theorems of differentiation?? pls pls

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The 1 that says if y = f(x) and k is a constant then dy/dx = k*df(x)/dx and the rest!!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is basically saying that the derivative of a constant times a function is that same constant times the derivative of the function. So, if you have \[f(x)= 4x^{2}\] and you want the derivative \[f'(x)= 4x^{2}dx\] it is the same as \[4f'(x)= x^{2}dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pls explain the other 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know the other two off the top of my head. If you post them I may be able to explain them.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 1 that says if y = u(x) + v(x) + w(x) then y' = u'(x) + v'(x) + w'(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative of a sum of functions is the sum of the derivatives of the functions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does u'(x) mean that it is the derivative of u(x)??????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, that is a common way of indicating derivative, along with d/du, etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if we were to write u(x) in its dy/dx form then it will still remain du/dx??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure I understand the question. in your statement above, "y = u(x) + v(x) + w(x) then y' = u'(x) + v'(x) + w'(x)", I assumed that u, v, and w are all some function of x. Thus u', v', w' are all derivatives of those functions with regard to x.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its just notation; there are many ways to express it
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