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anonymous

  • 5 years ago

Find the solution of a discrete dynamical system

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  1. anonymous
    • 5 years ago
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    hey btm I solved your problem

  2. anonymous
    • 5 years ago
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    http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dcaa12840ec8b0b88f50f17

  3. anonymous
    • 5 years ago
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    \[a _{0}=3 \]

  4. anonymous
    • 5 years ago
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    \[a _{n}=2a_{n-1}+ 2 \]

  5. anonymous
    • 5 years ago
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    thanks for that...

  6. anonymous
    • 5 years ago
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    this is another one and I have worked it out but doesn't seem to fit

  7. anonymous
    • 5 years ago
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  8. anonymous
    • 5 years ago
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  9. anonymous
    • 5 years ago
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    I got it

  10. anonymous
    • 5 years ago
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    a0=3 a1= 2(a0)+2 a2= 2(a1)+2 = 2[2(a0)+2]+2=2 (3 + 2 a0) a3= 2(a2)+2=2(3+2a0)+2=2 (7 + 4a0)

  11. anonymous
    • 5 years ago
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    ok...I will be back in 10 minutes...I have more if you can help

  12. anonymous
    • 5 years ago
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    a4=2 (15 + 8 a0]) At this point you should see a pattern aN= 2(2^n\[a_n=(2^n-1)+2^{n-1}a_0\]

  13. anonymous
    • 5 years ago
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    thanks...not checking out on calculator

  14. anonymous
    • 5 years ago
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    what do you mean?

  15. anonymous
    • 5 years ago
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    there is a way on graphing cal. to enter the system to check to see if the solution works

  16. anonymous
    • 5 years ago
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    it works by hand so thanks!

  17. anonymous
    • 5 years ago
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    I have two more...can you help

  18. anonymous
    • 5 years ago
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    sure,

  19. anonymous
    • 5 years ago
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    \[b _{0}=3\]

  20. anonymous
    • 5 years ago
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    \[b _{n}=.25b _{n-1}-1-n\]

  21. anonymous
    • 5 years ago
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    b1=.25*b0 - 1 - 1=0.25 (-8. +b0) b2=.25*b1 - 1 - 2=-3 + 0.25` (-2 + 0.25` b0)=0.0625 (-56. +b0) b3=-4 + 0.25 (-3 + 0.25 (-2 + 0.25 b0))=0.015625 (-312. + b0) The pattern I could figure out was \[b_n=.25^n[-( 4/9 (3* 2^{2 n} n+2^{2 n+1}-2) + b_0)\]

  22. anonymous
    • 5 years ago
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    thanks and last one

  23. anonymous
    • 5 years ago
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    \[r _{0}=3\]

  24. anonymous
    • 5 years ago
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    did you see the solution to your credit card problem?

  25. anonymous
    • 5 years ago
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    \[r _{n}=r _{n-1}+2\]

  26. anonymous
    • 5 years ago
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    have to go back and read/study it

  27. anonymous
    • 5 years ago
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    This one is rather easy

  28. anonymous
    • 5 years ago
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    r1=2+r0 r2=4+r0 r3=6+r0 I will let you figure out the pattern yourself

  29. anonymous
    • 5 years ago
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    yes it since it is linear and of order 1

  30. anonymous
    • 5 years ago
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    what year are you?

  31. anonymous
    • 5 years ago
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    ooopss have another one

  32. anonymous
    • 5 years ago
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    actually in graduate school for Educational Psychology but taking 1 credit math module for financial aid purposes...grrhhh

  33. anonymous
    • 5 years ago
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    but I'm learning some real life applications in the process

  34. anonymous
    • 5 years ago
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    \[d _{0}=3\]

  35. anonymous
    • 5 years ago
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    I am sure of the relation between psyc and this

  36. anonymous
    • 5 years ago
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    *I am not sure of the relation between psyc and this

  37. anonymous
    • 5 years ago
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    \[r _{n}=.65a _{n-1}+1.05(.5)^{n}\]

  38. anonymous
    • 5 years ago
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    I know that is why its is frustrating to figure this stuff out on my own without a professor

  39. anonymous
    • 5 years ago
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    a lot of work for 1 credit....

  40. anonymous
    • 5 years ago
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    1 credit hour?

  41. anonymous
    • 5 years ago
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    so I truly appreciate your help!

  42. anonymous
    • 5 years ago
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    YES!

  43. anonymous
    • 5 years ago
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    I don't think my uni has any 1 credit hour class

  44. anonymous
    • 5 years ago
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    approved modules for financial aid purpose...doesn't count towards degree...go figure!

  45. anonymous
    • 5 years ago
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    I remember some grad student in my physics, never knew why

  46. anonymous
    • 5 years ago
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    so frustrating but can't afford to pay out of pocket right now

  47. anonymous
    • 5 years ago
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    this is first and last semester taking this route...actually have 3 summer courses so don't have to worry about it then

  48. anonymous
    • 5 years ago
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    you going for phd?

  49. anonymous
    • 5 years ago
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    masters then maybe doctorate...

  50. anonymous
    • 5 years ago
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    did you see last problem

  51. anonymous
    • 5 years ago
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    Yea, working on it

  52. anonymous
    • 5 years ago
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    are you doing by hand

  53. anonymous
    • 5 years ago
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    most of it

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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