2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?

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- anonymous

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- anonymous

interent down, we had a bad storm roll through

- anonymous

yes still interested

- anonymous

By the way, did you realize that the phrasing of yesterdays problems were not good, and I conceived something which was not correct

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## More answers

- anonymous

For that problem on cumulative quadratic equation, .....

- anonymous

It meant that the equation itself provided the cumulative result

- anonymous

yes

- anonymous

So our result would be f(5)-f(4)

- anonymous

I am sorry, but the phrasing was too poor, and I didn't get it at all

- anonymous

sorry.. ok can you help me with this one?

- anonymous

- anonymous

Did you actually understand the problem ?

- anonymous

I mean did you understand what its saying?

- anonymous

no because i tried to use the formula 10e^.026(20) yet I get the wrong answer

- anonymous

Before using the formula you must understand what its being said...

- anonymous

What is the precise meaning of the term "given along with r"

- anonymous

time

- anonymous

?

- anonymous

I don't know, but I feel that it could have been better phrased

- anonymous

Is it from some book?

- anonymous

2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ? r is the 2.6

- anonymous

r is the decimal notation

- anonymous

Hey! I have the feeling you are actually phrasing the problem, it can't be from some printed material. Am I right?

- anonymous

thats what it says in the book, then it says write the formula PE^rx where r is the decimal notation

- anonymous

and that models the population in millions of years x after 1999

- anonymous

Listen the problem can't be solved if I don't understand the english. You see, I can't make out any thing from this part "its annual % rate of continuous growth P=10 Millions, r = 2.6% ". This is some kind of broken sentence. It makes no sense .

- anonymous

then it says the population in 2019 will be?

- anonymous

just a min I will write he whole thing and paste it correctly

- anonymous

Come here
https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB#

- anonymous

2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% - use the formula f(x) = PE^rx, where r is in decimal notation, that models the population in millions x years after 1999. The population in 2019 will be approximately ? million

- anonymous

Tell me what you wanted to say

- anonymous

I did it on the calc again

- anonymous

I did it like this 10e^(.037(20) and it came out with 17

- anonymous

I used extra parenthasis

- anonymous

(.037(20))

- anonymous

Yes, it is something around 16.8 ............

- anonymous

So is that ok?

- anonymous

I think so

- anonymous

how did you get 16.8?

- anonymous

So any more problem?

- anonymous

I just calculated using the calculator, thats it

- anonymous

how did you do it cause i got 17?

- anonymous

Come back to that place
https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB&pli=1#

- anonymous

I am sorry there was some connection problem here, I got disconnected. Please visit the link (given on the previous post) and post your email address....

- anonymous

I forgot your email address

- anonymous

\[A=10\times e^{.026\times 20}=10 e^{.52}=16.82\]
rounded. so 16.82 million

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