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anonymous

  • 5 years ago

2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?

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  1. anonymous
    • 5 years ago
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    interent down, we had a bad storm roll through

  2. anonymous
    • 5 years ago
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    yes still interested

  3. anonymous
    • 5 years ago
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    By the way, did you realize that the phrasing of yesterdays problems were not good, and I conceived something which was not correct

  4. anonymous
    • 5 years ago
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    For that problem on cumulative quadratic equation, .....

  5. anonymous
    • 5 years ago
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    It meant that the equation itself provided the cumulative result

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    So our result would be f(5)-f(4)

  8. anonymous
    • 5 years ago
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    I am sorry, but the phrasing was too poor, and I didn't get it at all

  9. anonymous
    • 5 years ago
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    sorry.. ok can you help me with this one?

  10. anonymous
    • 5 years ago
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    2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?

  11. anonymous
    • 5 years ago
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    Did you actually understand the problem ?

  12. anonymous
    • 5 years ago
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    I mean did you understand what its saying?

  13. anonymous
    • 5 years ago
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    no because i tried to use the formula 10e^.026(20) yet I get the wrong answer

  14. anonymous
    • 5 years ago
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    Before using the formula you must understand what its being said...

  15. anonymous
    • 5 years ago
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    What is the precise meaning of the term "given along with r"

  16. anonymous
    • 5 years ago
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    time

  17. anonymous
    • 5 years ago
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    ?

  18. anonymous
    • 5 years ago
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    I don't know, but I feel that it could have been better phrased

  19. anonymous
    • 5 years ago
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    Is it from some book?

  20. anonymous
    • 5 years ago
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    2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ? r is the 2.6

  21. anonymous
    • 5 years ago
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    r is the decimal notation

  22. anonymous
    • 5 years ago
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    Hey! I have the feeling you are actually phrasing the problem, it can't be from some printed material. Am I right?

  23. anonymous
    • 5 years ago
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    thats what it says in the book, then it says write the formula PE^rx where r is the decimal notation

  24. anonymous
    • 5 years ago
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    and that models the population in millions of years x after 1999

  25. anonymous
    • 5 years ago
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    Listen the problem can't be solved if I don't understand the english. You see, I can't make out any thing from this part "its annual % rate of continuous growth P=10 Millions, r = 2.6% ". This is some kind of broken sentence. It makes no sense .

  26. anonymous
    • 5 years ago
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    then it says the population in 2019 will be?

  27. anonymous
    • 5 years ago
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    just a min I will write he whole thing and paste it correctly

  28. anonymous
    • 5 years ago
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    Come here https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB#

  29. anonymous
    • 5 years ago
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    2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% - use the formula f(x) = PE^rx, where r is in decimal notation, that models the population in millions x years after 1999. The population in 2019 will be approximately ? million

  30. anonymous
    • 5 years ago
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    Tell me what you wanted to say

  31. anonymous
    • 5 years ago
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    I did it on the calc again

  32. anonymous
    • 5 years ago
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    I did it like this 10e^(.037(20) and it came out with 17

  33. anonymous
    • 5 years ago
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    I used extra parenthasis

  34. anonymous
    • 5 years ago
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    (.037(20))

  35. anonymous
    • 5 years ago
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    Yes, it is something around 16.8 ............

  36. anonymous
    • 5 years ago
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    So is that ok?

  37. anonymous
    • 5 years ago
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    I think so

  38. anonymous
    • 5 years ago
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    how did you get 16.8?

  39. anonymous
    • 5 years ago
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    So any more problem?

  40. anonymous
    • 5 years ago
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    I just calculated using the calculator, thats it

  41. anonymous
    • 5 years ago
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    how did you do it cause i got 17?

  42. anonymous
    • 5 years ago
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    Come back to that place https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB&pli=1#

  43. anonymous
    • 5 years ago
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    I am sorry there was some connection problem here, I got disconnected. Please visit the link (given on the previous post) and post your email address....

  44. anonymous
    • 5 years ago
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    I forgot your email address

  45. anonymous
    • 5 years ago
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    \[A=10\times e^{.026\times 20}=10 e^{.52}=16.82\] rounded. so 16.82 million

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