anonymous
  • anonymous
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?
Mathematics
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anonymous
  • anonymous
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
interent down, we had a bad storm roll through
anonymous
  • anonymous
yes still interested
anonymous
  • anonymous
By the way, did you realize that the phrasing of yesterdays problems were not good, and I conceived something which was not correct

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anonymous
  • anonymous
For that problem on cumulative quadratic equation, .....
anonymous
  • anonymous
It meant that the equation itself provided the cumulative result
anonymous
  • anonymous
yes
anonymous
  • anonymous
So our result would be f(5)-f(4)
anonymous
  • anonymous
I am sorry, but the phrasing was too poor, and I didn't get it at all
anonymous
  • anonymous
sorry.. ok can you help me with this one?
anonymous
  • anonymous
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ?
anonymous
  • anonymous
Did you actually understand the problem ?
anonymous
  • anonymous
I mean did you understand what its saying?
anonymous
  • anonymous
no because i tried to use the formula 10e^.026(20) yet I get the wrong answer
anonymous
  • anonymous
Before using the formula you must understand what its being said...
anonymous
  • anonymous
What is the precise meaning of the term "given along with r"
anonymous
  • anonymous
time
anonymous
  • anonymous
?
anonymous
  • anonymous
I don't know, but I feel that it could have been better phrased
anonymous
  • anonymous
Is it from some book?
anonymous
  • anonymous
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% Estimate the population in 2019 = ? r is the 2.6
anonymous
  • anonymous
r is the decimal notation
anonymous
  • anonymous
Hey! I have the feeling you are actually phrasing the problem, it can't be from some printed material. Am I right?
anonymous
  • anonymous
thats what it says in the book, then it says write the formula PE^rx where r is the decimal notation
anonymous
  • anonymous
and that models the population in millions of years x after 1999
anonymous
  • anonymous
Listen the problem can't be solved if I don't understand the english. You see, I can't make out any thing from this part "its annual % rate of continuous growth P=10 Millions, r = 2.6% ". This is some kind of broken sentence. It makes no sense .
anonymous
  • anonymous
then it says the population in 2019 will be?
anonymous
  • anonymous
just a min I will write he whole thing and paste it correctly
anonymous
  • anonymous
Come here https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB#
anonymous
  • anonymous
2) The population P in 1999 for a state is given along with r, its annual % rate of continuous growth P=10 Millions, r = 2.6% - use the formula f(x) = PE^rx, where r is in decimal notation, that models the population in millions x years after 1999. The population in 2019 will be approximately ? million
anonymous
  • anonymous
Tell me what you wanted to say
anonymous
  • anonymous
I did it on the calc again
anonymous
  • anonymous
I did it like this 10e^(.037(20) and it came out with 17
anonymous
  • anonymous
I used extra parenthasis
anonymous
  • anonymous
(.037(20))
anonymous
  • anonymous
Yes, it is something around 16.8 ............
anonymous
  • anonymous
So is that ok?
anonymous
  • anonymous
I think so
anonymous
  • anonymous
how did you get 16.8?
anonymous
  • anonymous
So any more problem?
anonymous
  • anonymous
I just calculated using the calculator, thats it
anonymous
  • anonymous
how did you do it cause i got 17?
anonymous
  • anonymous
Come back to that place https://docs.google.com/document/d/1dYgwObyfbr4lr-P_SHyZtFEUl9vvq7jruH0u6dHgXLU/edit?hl=en_GB&pli=1#
anonymous
  • anonymous
I am sorry there was some connection problem here, I got disconnected. Please visit the link (given on the previous post) and post your email address....
anonymous
  • anonymous
I forgot your email address
anonymous
  • anonymous
\[A=10\times e^{.026\times 20}=10 e^{.52}=16.82\] rounded. so 16.82 million

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