A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
The round trip flight took 3.9 h flying time. The plane traveled the 510 mi to the city at 255 mi/h with no wind. How strong was the wind on the return flight? Was the wind a head or tail wind?
anonymous
 5 years ago
The round trip flight took 3.9 h flying time. The plane traveled the 510 mi to the city at 255 mi/h with no wind. How strong was the wind on the return flight? Was the wind a head or tail wind?

This Question is Closed

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Let x= speed in mph on the return flight. 510/x=time distace/rate=time Now to figure time for the first half of the flight. distance =510 miles, rate was given as 255 mph. time=510/255 = 2 hours for the first half. Time for the round triip is given as 3.9h. Subtract 2 and you find the time for the return trip. 3.92=1.9. Since this is less time for the first part you can answer part of problem now. The wind was a tail wind. Now to the equation 510/x=1.9. 1.9x=510 x=268.421 mph How strong was the wind? 255268.421=13.42 mph tail wind.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.