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anonymous

  • 5 years ago

7u^2-28m^2 factor the polynomial

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  1. anonymous
    • 5 years ago
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    \[7(u ^{2}-4m ^{2})\] \[7(u+2m)(u-2m)\]

  2. anonymous
    • 5 years ago
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    do you understand how to do these type of problems?

  3. anonymous
    • 5 years ago
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    yes im just checking the problems to see if people come up with the same answer as me or something different

  4. anonymous
    • 5 years ago
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    ok, do you have any more?

  5. anonymous
    • 5 years ago
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    i have 7 more

  6. anonymous
    • 5 years ago
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    go ahead, ask away :)

  7. anonymous
    • 5 years ago
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    ok thank you this is the last thats factoring out the rest are solving the equations 16c^2+72cd+81d^2

  8. anonymous
    • 5 years ago
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    this might go faster if you tell me what you got for the answer and i'll check to make sure it's correct

  9. anonymous
    • 5 years ago
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    this one im thinking is prime

  10. anonymous
    • 5 years ago
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    which number do you think is prime?

  11. anonymous
    • 5 years ago
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    im thinking the polynomial is prime like the whole thing in other words it cant be factored down into a product of 2 binomials

  12. anonymous
    • 5 years ago
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    yes. first you should reorder the polynomial so it looks like this:\[72cd+16c ^{2}+81d ^{2}\] then factor \[(4c+9d)(4c+9d)\] \[(4c+9d)^{2}\]

  13. anonymous
    • 5 years ago
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    50b^2+20b+2=0 im thinking the solution to this is 1/5 -1/5

  14. anonymous
    • 5 years ago
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    how did you get the positive 1/5?

  15. anonymous
    • 5 years ago
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    i got the negative one first and the teacher said if the negative works then the positive will work as well and the other way around

  16. anonymous
    • 5 years ago
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    that's only the case when the variaable is squared or has a even number power. try plugging in the positive 1/5 in to the equation. does it come out to equal 0?

  17. anonymous
    • 5 years ago
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    no so it would be -1/5 and what would the other solution be then if its not positive 1/5

  18. anonymous
    • 5 years ago
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    -(1/5) is the only answer. the polynomial should look like this :\[2(25b ^{2}+10b+1)=0\]\[2(5b+1)(5b+1)=0\]\[5b+1=0\]\[b=-{\frac{1}{5}}\]

  19. anonymous
    • 5 years ago
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    sorry my computer is being tarded the next one is g^2+2/3g+1/9=0

  20. anonymous
    • 5 years ago
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    \[g=-{\frac{1}{3}}\]

  21. anonymous
    • 5 years ago
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    okk thanks thats all i needed for now youve been helpful thank you

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