anonymous
  • anonymous
7u^2-28m^2 factor the polynomial
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[7(u ^{2}-4m ^{2})\] \[7(u+2m)(u-2m)\]
anonymous
  • anonymous
do you understand how to do these type of problems?
anonymous
  • anonymous
yes im just checking the problems to see if people come up with the same answer as me or something different

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anonymous
  • anonymous
ok, do you have any more?
anonymous
  • anonymous
i have 7 more
anonymous
  • anonymous
go ahead, ask away :)
anonymous
  • anonymous
ok thank you this is the last thats factoring out the rest are solving the equations 16c^2+72cd+81d^2
anonymous
  • anonymous
this might go faster if you tell me what you got for the answer and i'll check to make sure it's correct
anonymous
  • anonymous
this one im thinking is prime
anonymous
  • anonymous
which number do you think is prime?
anonymous
  • anonymous
im thinking the polynomial is prime like the whole thing in other words it cant be factored down into a product of 2 binomials
anonymous
  • anonymous
yes. first you should reorder the polynomial so it looks like this:\[72cd+16c ^{2}+81d ^{2}\] then factor \[(4c+9d)(4c+9d)\] \[(4c+9d)^{2}\]
anonymous
  • anonymous
50b^2+20b+2=0 im thinking the solution to this is 1/5 -1/5
anonymous
  • anonymous
how did you get the positive 1/5?
anonymous
  • anonymous
i got the negative one first and the teacher said if the negative works then the positive will work as well and the other way around
anonymous
  • anonymous
that's only the case when the variaable is squared or has a even number power. try plugging in the positive 1/5 in to the equation. does it come out to equal 0?
anonymous
  • anonymous
no so it would be -1/5 and what would the other solution be then if its not positive 1/5
anonymous
  • anonymous
-(1/5) is the only answer. the polynomial should look like this :\[2(25b ^{2}+10b+1)=0\]\[2(5b+1)(5b+1)=0\]\[5b+1=0\]\[b=-{\frac{1}{5}}\]
anonymous
  • anonymous
sorry my computer is being tarded the next one is g^2+2/3g+1/9=0
anonymous
  • anonymous
\[g=-{\frac{1}{3}}\]
anonymous
  • anonymous
okk thanks thats all i needed for now youve been helpful thank you

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