7u^2-28m^2 factor the polynomial

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

7u^2-28m^2 factor the polynomial

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[7(u ^{2}-4m ^{2})\] \[7(u+2m)(u-2m)\]
do you understand how to do these type of problems?
yes im just checking the problems to see if people come up with the same answer as me or something different

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok, do you have any more?
i have 7 more
go ahead, ask away :)
ok thank you this is the last thats factoring out the rest are solving the equations 16c^2+72cd+81d^2
this might go faster if you tell me what you got for the answer and i'll check to make sure it's correct
this one im thinking is prime
which number do you think is prime?
im thinking the polynomial is prime like the whole thing in other words it cant be factored down into a product of 2 binomials
yes. first you should reorder the polynomial so it looks like this:\[72cd+16c ^{2}+81d ^{2}\] then factor \[(4c+9d)(4c+9d)\] \[(4c+9d)^{2}\]
50b^2+20b+2=0 im thinking the solution to this is 1/5 -1/5
how did you get the positive 1/5?
i got the negative one first and the teacher said if the negative works then the positive will work as well and the other way around
that's only the case when the variaable is squared or has a even number power. try plugging in the positive 1/5 in to the equation. does it come out to equal 0?
no so it would be -1/5 and what would the other solution be then if its not positive 1/5
-(1/5) is the only answer. the polynomial should look like this :\[2(25b ^{2}+10b+1)=0\]\[2(5b+1)(5b+1)=0\]\[5b+1=0\]\[b=-{\frac{1}{5}}\]
sorry my computer is being tarded the next one is g^2+2/3g+1/9=0
\[g=-{\frac{1}{3}}\]
okk thanks thats all i needed for now youve been helpful thank you

Not the answer you are looking for?

Search for more explanations.

Ask your own question