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the y is the heavy side; so this opens up and down

teh distance between the foci is 8; so each foci is 4 from center; that 4 is either a or c :)

ok so a

we have 4 between the vertices; so each vertex is 2 from center

right how do I find b^2 then?

under the y we have 2^2 right? let me look this up some more :)

ok I think actually I have to know what c^2 is
cause C^2=a^2+b^2

I'm thinkin' b^2=16...?

tell me your understanding of a b and c; what do they measure?

the foci are c units from the center
the vertices are a units from the center

so; a^2 + b^2 = c^2 then right?

2 + b^2 = 64
b^2 = 62 then

I think so....but that doesn't eem right maybe it's minus?

my options for b^2 are 12 or 16 here but I don't see how they get either of those

i used 8 instead of 4 :)

i think so...

16-4 = 12

b^2 = 12

oh ok I was gonna say 16 cause 4^2=16 but 12 works too

the minor axis is always smaller in number than the major axis

since the major is the y on this one; and it is 16; the other has to be less

or maybe i messed that up in thougth