Find the standard form of the equation of the hyperbola with the given characteristics.
vertices: (2, - 6), (2, - 2)
foci: (2, - 8), (2, 0)
I know this much so far:
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the y is the heavy side; so this opens up and down
teh distance between the foci is 8; so each foci is 4 from center; that 4 is either a or c :)
oh ok I was gonna say 16 cause 4^2=16 but 12 works too
the minor axis is always smaller in number than the major axis
since the major is the y on this one; and it is 16; the other has to be less
or maybe i messed that up in thougth
ugh... idk this is all a review for my final and I am thinking that so far i'm not doing too hot. YIKES
--- - --- = 1
b^2 = focal distance(c)^2 - vertex distance(a)^2
in this case; the hyperbola; c is the greatest distance beacusae it is used as the hypotenust
in the ellipse; a is the greatest distance becasue IT is used for ITS hypotenuse