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anonymous
 5 years ago
i need to find the tan(ab) knowing tan a=5/12, sin $= 4/5 and sec B= 25/24 the restriction is (pi/2)<$<a<(3pi/2)<B<2pi. This is for precalc class and is kind of my last resort... I don't know how this site works actually, but please help ^^
anonymous
 5 years ago
i need to find the tan(ab) knowing tan a=5/12, sin $= 4/5 and sec B= 25/24 the restriction is (pi/2)<$<a<(3pi/2)<B<2pi. This is for precalc class and is kind of my last resort... I don't know how this site works actually, but please help ^^

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is dollar here? I guess you should use the fact that tan(ab)=(tanAtanB)/(1+tanAtanB)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i didn't have a theta so i just put that instead. !! I used that but i keep getting the wrong answer so feel like im doing it wrong. Supposedly the answer is 204/253... D:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you use sin(theta)=4/5 ? I cannot see how it can be.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i didn't use it because i didn't think it was important to the equation D:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok than how did you find out sin a?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i drew a triangle and used pythagorean to find the other side. Why do i need the sin? it's not even in the problem... is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you find sin a than you are basically done, but it is not necessary I guess.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I feel bad now, I am doing calculus now, but I would not be able to solve this :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's ok i fail even more XD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try posting it again, hoping some wiser guy will help you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok then thanx anyway ^^
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