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anonymous
 5 years ago
simplify 8^2/3 x 2^1/3
anonymous
 5 years ago
simplify 8^2/3 x 2^1/3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[8=2^{3} so... 8^{(2/3)}=2^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you have 2^2 * 2^(1/3). Add the exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[8^{\frac{2}{3}}\] means cube root of 8 squared. cube root of 8 is 2, 2 squared is 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02 + (1/3) = 5/3 So the answer would be 2 ^ (5/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in order to simplify, you have to have a common base. So by simplifying the 8, you can get everything written with a base of 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they are added...not multiplied?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like satellite said, the cube root of 8 is 2, so that gives you 2^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, when multiplying, you add the exponents....think x^2*x^3 = x^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand the first number, not the second 2^(1/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, since they both have a base of 2, you can add their exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok...gotcha on the addition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You don't have to change anything in 2^(1/3), since it alrady has a base of 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you get 5/3 by adding 1/3 and 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0get common denominators....2 = 6/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im new to this site. how exactly does it work...students helping students?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have a few more of these problems, but i want to try them myself...try at least lol
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