## anonymous 5 years ago Given cos 2θ=-1/2 and 2θ ends in quadrant II. Find cotθ

1) solve for $\theta$ $2\Theta=4\pi/3$ $\theta=2\pi/3$ it's means that: $\cot \theta =\cot (2\pi/3)=(-1/2) /(\sqrt{3}/2) = -1/\sqrt{3}$