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anonymous
 5 years ago
Which of the following is equivalent to the expression below?
1+sec(theta)

tan(theta)+sin(theta)
anonymous
 5 years ago
Which of the following is equivalent to the expression below? 1+sec(theta)  tan(theta)+sin(theta)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1 + sec(\theta)}{tan(\theta) + sin(\theta)} = \frac{1 + \frac{1}{cos(\theta)}}{\frac{sin(\theta)}{cos(\theta)} + sin(\theta)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dunno what options you have, these trig identities can get complicated.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0csc(theta) tan(theta) 1 sec(theta) cot(theta)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, from the denominator you can factor out a sin(theta) from each term.. what do you have then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uh (1+1/cos(theta))/(cos(theta))?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no. try factoring again \[\frac{sin\theta}{cos\theta} + sin\theta = ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's the answer yes, but not what I was asking.. I assume you saw the solution after you factored it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0err actually no, that's not the answer. nvm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you get when you factor out a sin(theta) from that expression in the denominator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uhhhh ok how do I factor it out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you factor out the a from 2a + ba ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or factor out a 2 from (4 + 6a)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(theta)(1/cos(theta)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try this one: factor completely (10x+2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right. Now try \(\frac{a}{b} + a\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or we can write it as\[\frac{1}{b}*a + a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if that makes it clearer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(θ)(1+cos(θ))/cos(θ)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{a}{b} + a = a(\frac{1}{b} + 1). a = sin(\theta), b = cos(\theta) \]\[\implies \frac{sin(\theta)}{cos(\theta)} + sin(\theta) = sin\theta(\frac{1}{cos\theta} + 1)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok.... i guess i was kinda close, but not really

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so from there you should see something nice to cancel and get a simple answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Like the [1 + 1/cos(theta)] you have on top and bottom

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what equation are you looking at?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1+\frac{1}{cos\theta}}{sin\theta (1 + \frac{1}{cos\theta})}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so all I have left is 1/sin(theta)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which equals...csc(theta)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow sorry about making that so difficult thank you so much!
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