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2x +5/10x + 3 = 1/3
25/10x+3=1/3
25/10x=-8/3
x=-16/15

where did 25 come from

majic

I made 2x into a fraction and found a common denominator to combine 2/1+5/10

i dont know im sorry

polpak could you help me with my question by chance?

\[2x = \frac{2x*10x}{10x} = \frac{20x^2}{10x}\]

let me take a moment to look it...take it in lol

np, I was just correcting mm

Just multiply both sides by 10x with the requirement that x cannot be 0

polpak, do you mind showing me step by step

Well I told you the first step.. what do you have when you multiply both sides by 10x?

sorry...interrupted

(2x+5)/3 = 10x/3

where did the /3 on the left come from??

wait.. is the original equation
\[\frac{2x + 5}{10x + 3} = \frac{1}{3}\]

yeah

you need to use parens better when describing the problem ;p

ok, so multiply both sides by 10x + 3 (with the stipulation that x cannot be -3/10)

so far i have 2x + 4 = 10x/3...on the right track?

no. you should have 2x + 5 = (10x + 3)/3

i skipped to the next step...where 3/3 = 1 and then subtracted from other side...does x=1

You can't do that

Oh, I see

Err wait. What did you do? x=1 isn't right

4/5?

no

Show your work so I can figure out what you're doing

so 2x + 5 = 10x +1 is that correct and i can go from there

No

i know what i did...just noticed that...i started over with a clean piece of paper

so 6x + 15 = 30x + 9

no

i left my brain behind...sorry

np, it happens =)

\[3(2x + 5) = \frac{3(10x + 3)}{3}\]

you should have that written on your paper

so which 3's should cancel eachother out?

\[\frac{3(10x + 3)}{3} = \frac{3}{3}(10x + 3) = 1(10x + 3) = 10x + 3\]

ok...that was my problem....i wanted to cancel out the wrong 3...noted

x = 3

indeed

finally lol....sorry this has been a chore...thanks for your help and patience

definitely will...starred it on my sheet as "needs more attention" lol

good job =)

thanks :)