2x +5/10x + 3 = 1/3 solve for x

- anonymous

2x +5/10x + 3 = 1/3 solve for x

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- anonymous

2x +5/10x + 3 = 1/3
25/10x+3=1/3
25/10x=-8/3
x=-16/15

- anonymous

where did 25 come from

- anonymous

majic

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## More answers

- anonymous

I made 2x into a fraction and found a common denominator to combine 2/1+5/10

- anonymous

i dont know im sorry

- anonymous

polpak could you help me with my question by chance?

- anonymous

\[2x = \frac{2x*10x}{10x} = \frac{20x^2}{10x}\]

- anonymous

let me take a moment to look it...take it in lol

- anonymous

np, I was just correcting mm

- anonymous

Just multiply both sides by 10x with the requirement that x cannot be 0

- anonymous

polpak, do you mind showing me step by step

- anonymous

Well I told you the first step.. what do you have when you multiply both sides by 10x?

- anonymous

sorry...interrupted

- anonymous

(2x+5)/3 = 10x/3

- anonymous

where did the /3 on the left come from??

- anonymous

wait.. is the original equation
\[\frac{2x + 5}{10x + 3} = \frac{1}{3}\]

- anonymous

yeah

- anonymous

you need to use parens better when describing the problem ;p

- anonymous

ok, so multiply both sides by 10x + 3 (with the stipulation that x cannot be -3/10)

- anonymous

so far i have 2x + 4 = 10x/3...on the right track?

- anonymous

no. you should have 2x + 5 = (10x + 3)/3

- anonymous

i skipped to the next step...where 3/3 = 1 and then subtracted from other side...does x=1

- anonymous

You can't do that

- anonymous

Oh, I see

- anonymous

Err wait. What did you do? x=1 isn't right

- anonymous

4/5?

- anonymous

no

- anonymous

Show your work so I can figure out what you're doing

- anonymous

so 2x + 5 = 10x +1 is that correct and i can go from there

- anonymous

No

- anonymous

You have to divide the whole 10x + 3 by 3, you can't just divide the 3 on top and leave the 10x alone. I suggest instead multiplying both sides by 3 to get rid of the fraction

- anonymous

i know what i did...just noticed that...i started over with a clean piece of paper

- anonymous

so 6x + 15 = 30x + 9

- anonymous

no

- anonymous

you forgot that the part on the right was divided by 3, so multiplying by 3 just cancels the denominator on the right side

- anonymous

i left my brain behind...sorry

- anonymous

np, it happens =)

- anonymous

give me one minute..going to reason through...what bothers me the most...is that this looks simple and i feel like i can solve more difficult problems more easily

- anonymous

\[3(2x + 5) = \frac{3(10x + 3)}{3}\]

- anonymous

you should have that written on your paper

- anonymous

so which 3's should cancel eachother out?

- anonymous

\[\frac{3(10x + 3)}{3} = \frac{3}{3}(10x + 3) = 1(10x + 3) = 10x + 3\]

- anonymous

ok...that was my problem....i wanted to cancel out the wrong 3...noted

- anonymous

x = 3

- anonymous

indeed

- anonymous

finally lol....sorry this has been a chore...thanks for your help and patience

- anonymous

np, just be sure to go back over the process and make sure you understand not only what we did, but why what you were doing doesn't work

- anonymous

definitely will...starred it on my sheet as "needs more attention" lol

- anonymous

good job =)

- anonymous

thanks :)

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