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anonymous
 5 years ago
how do i find max/or min value of a function algebraically  the function is g(x)=3x^22x1
anonymous
 5 years ago
how do i find max/or min value of a function algebraically  the function is g(x)=3x^22x1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its a parabola and the leading coefficient is positive , so it will have a min at its vertex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since g is of the form \[g(x)=ax^2+bx+c\] the formula for the ordered pair that is the vertex is given by \[(x,y)=(\frac{b}{2a},g(\frac{b}{2a}))\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the x value matches the calc min x value! now i just have to do my y so what is the value of g to calcuate that? the value im supposed to get is 1.3333333.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes (1/3,4/3) is the vertex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just evaluate g at x=1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i.e. \[g(1/3)=3(1/3)^22(1/3)1=4/3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh so basically just substituting the x value back into the equation! thanks so much!
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