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im bad at geometry!

1/2 x Breadth x Height

\[Area_{\Delta} = \frac{1}{2}Base \times Height\]

i know. but i need help solving a question.!

im sorry its base.

post your question here!

Breadth is a decent word for it

ok hold on.

use 1.7 as the value of square root 3. what is the area of equalateral triangle abc in sq. in

what are the lengths of the sides of the triangle?

here ill send a picture.

Ok, so what is the length of the base?

I don't know..

its equilateral

4?

yes

Ok.

so now we need the height (the length of the blue line through the middle)

how?

pythagoras theorem

Well, we have 2 right triangles described in the middle of that equalateral triangle.

yes.

\[2^{2} + x ^{2} = 4^{?}\]

its 2?

\[x = \sqrt{4^{2}-2^{?}}\]

which is sqrt of (16 - 4)

which is sqrt 12.

since sqrt 3 is given by 1.7

yes,

sqrt 12 = sqrt(4x3)

sqrt(4x3) = 2x(sqrt3)

which is 2x1.7 = 3.4, therefore the length is 3.4 and the base 4.

using the formula 1/2 b h = 0.5 x 3.4 x 4.

the answer is 6.8 inches

are u sure

this means you don't understand how it's done!

the more important question is are YOU sure.

Because if you aren't sure, then you have no way to know if holy did it right.

yes.

NO I UNDERSTAND! :) now.

can u guys help me with one more like that?

its the same question as the previous. if you understood you should be able to do this.

since its an equilateral triangle. use the formula to get the length of the triangle.

using the formula \[a ^{2} + b ^{2} = c ^{2}\]

you can find out what is the height/length of the triangle.