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anonymous

  • 5 years ago

Can someone pleaseeee . help me.

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  1. amistre64
    • 5 years ago
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    cant help without knowing the problems

  2. anonymous
    • 5 years ago
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    ill send it in a pic

  3. anonymous
    • 5 years ago
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  4. amistre64
    • 5 years ago
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    the area of the equi lateral eh..

  5. amistre64
    • 5 years ago
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    12*12*sin(60) ------------ 2 sin(60) = sqrt(3)/2

  6. amistre64
    • 5 years ago
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    36*sqrt(3)

  7. anonymous
    • 5 years ago
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    30.6

  8. anonymous
    • 5 years ago
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    30.6

  9. anonymous
    • 5 years ago
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    is that the answer

  10. amistre64
    • 5 years ago
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    36 1.7 --- 252 360 ----- 385.2 ??

  11. anonymous
    • 5 years ago
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    is that the answer...?

  12. amistre64
    • 5 years ago
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    should be; 12*12*sqrt(3) ------------ = 36 * sqrt(3) 2*2

  13. anonymous
    • 5 years ago
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    im confused. soooo.... 36?

  14. anonymous
    • 5 years ago
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    NEvermind i got it i need help with a dif. prob

  15. anonymous
    • 5 years ago
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  16. anonymous
    • 5 years ago
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    \[Area = (1/2)base \times height = (12/2) \times \sqrt{3}(6) = 6 \times (1.7)(6) = 61.2\]

  17. anonymous
    • 5 years ago
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    is that for the question i just posted. i just sent a new one

  18. amistre64
    • 5 years ago
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    base = side height = side * sin(angle) .... ok? base = 12; height = 12 sin(60)

  19. anonymous
    • 5 years ago
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    what question is that for.

  20. amistre64
    • 5 years ago
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    first one....

  21. anonymous
    • 5 years ago
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    i need it for the one i posted just now

  22. anonymous
    • 5 years ago
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  23. anonymous
    • 5 years ago
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    Can someone just give me the answer.:(

  24. amistre64
    • 5 years ago
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    we can do it this way to to prove my point; sqrt(12^2 - 6^2) = height sqrt(144 - 36) = sqrt(108) Area = sqrt(108)*12/2 = 62.35 .................................................... musts hit a wrong button lol

  25. anonymous
    • 5 years ago
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    i don't need it for that question. i need it for the one I JUST NOW POSTED.

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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