anonymous
  • anonymous
Can someone pleaseeee . help me.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
cant help without knowing the problems
anonymous
  • anonymous
ill send it in a pic
anonymous
  • anonymous

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More answers

amistre64
  • amistre64
the area of the equi lateral eh..
amistre64
  • amistre64
12*12*sin(60) ------------ 2 sin(60) = sqrt(3)/2
amistre64
  • amistre64
36*sqrt(3)
anonymous
  • anonymous
30.6
anonymous
  • anonymous
30.6
anonymous
  • anonymous
is that the answer
amistre64
  • amistre64
36 1.7 --- 252 360 ----- 385.2 ??
anonymous
  • anonymous
is that the answer...?
amistre64
  • amistre64
should be; 12*12*sqrt(3) ------------ = 36 * sqrt(3) 2*2
anonymous
  • anonymous
im confused. soooo.... 36?
anonymous
  • anonymous
NEvermind i got it i need help with a dif. prob
anonymous
  • anonymous
anonymous
  • anonymous
\[Area = (1/2)base \times height = (12/2) \times \sqrt{3}(6) = 6 \times (1.7)(6) = 61.2\]
anonymous
  • anonymous
is that for the question i just posted. i just sent a new one
amistre64
  • amistre64
base = side height = side * sin(angle) .... ok? base = 12; height = 12 sin(60)
anonymous
  • anonymous
what question is that for.
amistre64
  • amistre64
first one....
anonymous
  • anonymous
i need it for the one i posted just now
anonymous
  • anonymous
anonymous
  • anonymous
Can someone just give me the answer.:(
amistre64
  • amistre64
we can do it this way to to prove my point; sqrt(12^2 - 6^2) = height sqrt(144 - 36) = sqrt(108) Area = sqrt(108)*12/2 = 62.35 .................................................... musts hit a wrong button lol
anonymous
  • anonymous
i don't need it for that question. i need it for the one I JUST NOW POSTED.

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