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anonymous

  • 5 years ago

Please need help. Ill send a prob in pic.

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  1. anonymous
    • 5 years ago
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    help what?

  2. anonymous
    • 5 years ago
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    are you good at geometry?

  3. anonymous
    • 5 years ago
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    I don't so so If not too hard I help my son geometry now I can try

  4. anonymous
    • 5 years ago
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  5. anonymous
    • 5 years ago
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    ive replied in ur earlier question

  6. anonymous
    • 5 years ago
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    i see. don't get the answer tho.

  7. anonymous
    • 5 years ago
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    plug in 16 for a

  8. anonymous
    • 5 years ago
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    i still don't get it. i SUCK at math.

  9. anonymous
    • 5 years ago
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    see il explain

  10. anonymous
    • 5 years ago
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    doesn' say angles degree , but given use square 3 I can tell, hypotenuse = twice time shot leg 16/2=8 than CB = 8*2=16 \[\sqrt{3}* 16= the heigh\]

  11. anonymous
    • 5 years ago
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    if u drop a perpendicular to a base from any vertex, it divides ur equilateral triangle into two halves

  12. anonymous
    • 5 years ago
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    if the side of your equilateral triangle is a, the base of each of these 2 triangles is a/2

  13. anonymous
    • 5 years ago
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    \[\sqrt{3}* 8 \]not 16 sorry

  14. anonymous
    • 5 years ago
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    like him say the side divi haft triangle 16/2=8 the heigh = square3* 8 CB=8*2=16

  15. anonymous
    • 5 years ago
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    \[\sqrt{16^{2}-8^{2}}=13.9\] A=(16*13.9)/2 A=111.2

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spraguer (Moderator)
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