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amistre64
 5 years ago
What does the scalar result of dotting 2 vectors signify? I know a 0 means they are perps, but what is the scalar product actually mean?
amistre64
 5 years ago
What does the scalar result of dotting 2 vectors signify? I know a 0 means they are perps, but what is the scalar product actually mean?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<1,1>.<0,2sqrt(2)> = 0 + 2sqrt(2) = 2sqrt(2). That doesnt make sense to me a whole lot.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that just seems to give the magnitude of the bottom vector

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0<1,1>.<0,2sqrt(2)> = 0 + 2sqrt(2) = 2sqrt(2). how?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0It gives the cosine of the angle between them. This is the way you can get angles in any vector space with an inner product.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<1 , 1 > <0,2sqrt(2)>  0 + 2sqrt(2) = 2sqrt(2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes, it gives the adjacent part of the cosine angle which is just the magnitude of the bottom vector right? the product of the magnitudes of the top and bottom vectors account for the 'hypotenuse' then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0<1 , 1 > <0,2sqrt(2)>  0 + 2sqrt(2) = 2sqrt(2). iam not geting it amistre

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1see; it is how you multiply vectors; or at least one way to do it; the other being the cross product

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1cross product can be found two ways if i remember correctly finding the determinant of a matrix or some kind of trig thing right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1determinate of 2 vectors is usual

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the other way is just to equate the zero dot product of 2 vectors inthe plane and equat them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1v<x,y> n<a,b>  vx.a + vy.b = 0 u<x,y> n<a,b>  ux.a +uy.b = 0 equate them and solve the system of equations :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1geterminate is mor emechanical tho

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol... read thru the typos

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i now the scalar projection projects the top onto the bottom at topcos(a)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i just dont understand if there is another way to use the scalar product other than associating it to the cos(a) between the 2 vectors :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1example: find u*v if u=2i+3j and v=2k  i j k  = i3 0  j2 0 +k2 3 =i(2(3)0)j(20)+k(00)=6i+2j  2 3 0  0 2 0 2 0 0  0 0 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1correct; just keep in mind to do ++ :) that middle  is to account for being lazy i think lol

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i forgot about that othr two up there

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12a+3b+0c = 0 0a+0b2c = 0 lol... thats would be hard to determine that way ; cross product is better in that case; and in most cases prolly

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1yes that would be hard lol (or impossible) i dont see how we could do it that way
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