anonymous
  • anonymous
Amistre64, are you out there? I need help! the question is: find the absolute maximum and minimum values of the function in given interval. f(theta)=cos theta -2less than or equal to theta less than or equal to -3pi/4.
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
im out here somewhere in the eternal ether :)
anonymous
  • anonymous
Actually, i typed some of that wrong. It's the interval of -2pi less than or equal to theta less than or equal to -3pi/4
amistre64
  • amistre64
its a simple cos function.... nothing modifying it so it should be easy for us to accomplish :)

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anonymous
  • anonymous
Just fyi i know NOTHING about converting thetas to square roots.
amistre64
  • amistre64
-2pi to 0 has a max at 0; a max at -2pi and a min at pi this is just pointing out where the graph bends at between -2pi and -3pi/4 which i went a little far
amistre64
  • amistre64
-2pi = max - pi = min and that all you get in that interval
anonymous
  • anonymous
I don't get it. Where are the max and min values in that? I know nothing abou this!
amistre64
  • amistre64
the cosine graph is just a wave that bounces between 1 and -1
amistre64
  • amistre64
at 0 or any even multiples of pi; cos(x) = 1 at pi or any odd multiples cos(x) = -1
anonymous
  • anonymous
How did you figure that out? What is the actual value of the max at -2pi? and -pi? Aren't they like answers in terms of square roots or pi or something?
amistre64
  • amistre64
we could take the derivative which is -sin(x) but that doesnt help out much unless you know the graph for it as well :)
amistre64
  • amistre64
nah; the max of cos(x) = 1 the min of cos(x) = -1
amistre64
  • amistre64
cos(-2pi) = 1 cos(-pi) = -1
amistre64
  • amistre64
thats just the definition for cosine...
amistre64
  • amistre64
Dx(cos(x)) = -sin(x) -sin(x) = 0 at..... -2pi, and -pi in between [-1pi,-3pi/4]
anonymous
  • anonymous
Ok, here's how they want the answer and I can't figure out what you are telling me. They want "Absolute maximum is ____ at theta=_____
anonymous
  • anonymous
Then "Absolute minimum is ____ at theta=____"
amistre64
  • amistre64
1 Attachment
amistre64
  • amistre64
absolute min = -1 at -pi
amistre64
  • amistre64
absolute max = 1 at -2pi
anonymous
  • anonymous
Bless you, dear. But HOW DO YOU KNOW THIS? is there a table of values? I just started this in calculus, and I am sure i will need it in the future, and unless you want to take my next calc exam... seriously where i find the equations for this? Like what does sin(5pi/3 equal? Where do I find those values or is there a conversion with a formula?
amistre64
  • amistre64
its from trig class; trig is just memorizing angles and sin cos tan stuff
anonymous
  • anonymous
ok but where do you find the angles to memorize? Like i said, is there a table or something? A formula? What? there has to be some way to figure this out!!!!!
amistre64
  • amistre64
yeah, look up 'trig tables' and 'trig graphs' in google; theyll give you alot to pick from :)
anonymous
  • anonymous
ok, btw, not that you doubted your brain power or anything, but of course you were right and figured out in 3 seconds what i have been trying to figure out for literally 43 hours. 1 problem...3 hours??? I can't do that for 50 problems!!! These tables will help?
anonymous
  • anonymous
i did not mean 43 hours, i meant 3
amistre64
  • amistre64
:) they will help. And when i dont use trig for a while im bound to forget them ;)
anonymous
  • anonymous
do you do this math stuff for fun? because you love it so much? you must because you don't get paid to help dummies like me!!! ; )
amistre64
  • amistre64
lol... i do enjoy math; its the one constant in my life :)
anonymous
  • anonymous
yay for you. i enjoy it too, more on the algebra end, but i am not good at it naturally; I struggle to learn it. Trying to take a calc course online is like literally teaching myself everything there is to know about calc! Not sure I will be as successful as you are at it!
amistre64
  • amistre64
ive taught myself up to about calc4 so far; its easy once you get past the tedium of limits and longhand version of derivatives and integrals
amistre64
  • amistre64
well, derivatives are pretty straight forward; integrals can be tricky because its more art than science
anonymous
  • anonymous
oh my gosh. I could only wish to be that smart! Thank you so much! I don't know wht time it is there, but it is almost 3 am here in Illinois and I have to be up with the kids in like 3 hours1 This math will literally be the death of me! Thank you thank you thank you again and again! I'm sure i will talk to to you VERY soon. Rachel.
anonymous
  • anonymous
Good night, and thanks again.
amistre64
  • amistre64
Nite , im in florida ;)
anonymous
  • anonymous
So its like almost 4 am there!
amistre64
  • amistre64
illinois is one of them mormon states i believe
amistre64
  • amistre64
330am if the computer is right ;)
anonymous
  • anonymous
yes it is it's 2:30 here. crazy!
anonymous
  • anonymous
ttyl, thanksoncemore

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