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my guess is 72

or do you mean all permutations?

It's not 72.

help please! ><

its aolt of counting :)

didnt really help.. :/

9C2 x 10C2 isn't a lot of counting.

It's a lot of counting if you apply a medieval method, sure.

anyway. i have another question

i can explain how i derive mine. by doing the board from 1x1, 2x2,3x3, 4x4, it produces the answer

1x1 -> 0

2x2-> 4
3x3-> 16
4x4-> 36

Firstly, a square is a type of rectangle.

which follows a pattern of \[(2n-2)^{2}\]

states*

for my benefit in this case i chose not to.

Firstly, you cannot decide a square isn't a rectangle. And second, your answer is still wrong.

why is a square a rectangle?

all squares are rectangles; but not all rectangles are squares.

rectangle = opposites sides are the same; and 4, 90 degree corners

Just a note - there was a typo above -> 3x3 gives 36 not 37.

actually a rectangle is a shape that has 2 equal sides.

which makes square also a rectangle. ok i had that clarified thanks.

a parallelogram is also a rectangle

3*3=36. HOW?

*facepalm*

its 1^3 + 2^3 + 3^3

LOL. and newton who are you anyway? ^^

IF IT IS 3^3 THEN ANSWER IS 27 NOT 36???

at leat no mistakes that anyone has lived to tell about ;)

LOL. are you a lecturer? >.>

YOU R SAYING IT IS NOT A MISTAKE? FUNNY

how do you remove see out of this conversation?

btw newton. can you help me in 8x9 rectangles?

ANY THING WRONG HOLYX?????????????

8 by 9*

Ugh, LaTeX fail:
\[^{10}C_2 \]**

you mean 8!/(8-r)!r!

wait im thinking. lol

i dont get it. why 10c2. x 9c2. why do you need to multiply.

Ugh, I mixed up vertical and horizontal in each part, but hopefully it made sense.

ok yea. 9c2 x 9c2 gives the same aswer 1296!

:)

omg. you're damn smart. how did you thought of that. -,- wtf.

anyway thanks for answering my question (: