Suppose that lim n->infinity.....

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Suppose that lim n->infinity.....

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\lim_{n \rightarrow \infty} a _{n} =4 \] and \[\lim_{n \rightarrow \infty} b _{n} =7 \] Determine \[\lim_{n \rightarrow \infty} (a _{n}+b _{n})\]
11
how?

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Other answers:

11? lol. its simple.
oh JUUST KIDDING LOL
I put the wrong equation!
........
u cn break the bracket and apply limits individually if its a sum
\[\lim_{n \rightarrow \infty} a _{3}^{n}\]
still 4.
as n tends to infinity. infinity over 3 is still infinity.
what about \[\lim_{n \rightarrow \infty} 4b _{n}\]
28
yup.
\[4\lim_{n \rightarrow \infty}b _{n}= 4 x 7\]
okay last one ; \[\lim_{n \rightarrow \infty}(a _{n}^{2} - 2a _{n}b _{_{n}})\]
-40
4^2 - 2x4x7 = -40
yeah...
SO FAST!?!?
who me?
both
him was way faster. its just simple calculation btw.
yeah . just gotta plug things in
thanx holy...

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