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anonymous
 5 years ago
I got a doubt in limits see below for my question
anonymous
 5 years ago
I got a doubt in limits see below for my question

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}\]\[sinax / tanbx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is the actual question \[\lim_{x \rightarrow 0} sinax/tanbx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differentiate top and bottom acos(ax) / b sec^2 (bx)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply and divide by bx/ax

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know differntiation and u mean that i should multiply the numerator by ax/ax and denominator by bx/bx????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont even know what him was on bout either lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you havent done derivatives then your teacher shouldnt be giving you this question !

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this can be done without derivatives

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's wat i am saying him1618 you are right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how? , and its much easier with derivatives, 2lines of work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not pinching theorm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah its easier..no doubt 110 times out of 100 id use derivatives, but the fact is that if hes doing limits fundamentally its imperative for him to know the fundamental steps..rather than shortcuts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i guess he wants a legitimate fundamental method which uses standard limit definitions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0exactly now can u pls explain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first divide above and below by x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then make a form like this \[[\sin( ax )/ax] /[\tan (bx)/bx] \] x a/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the book i am goin through says multiply the numerator by ax/ax and the denominator by bx/bx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats right..dont look at the solns..which book is this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u understood wt i did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope the book is my coaching book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did not understand wat wud happen if i divided by x????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok divide sin ax by ax and tan bx by bx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then you will have to multiply by a/b also, to keep it the same..understand?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so sinax by ax, with x tending to zero is 1, and so is tanbx by bx so the ans is 1 x a/b a/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh I remember that way , just the way the question looked put me off lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also, I just differentiate top and bottom etc, its so easy and there no brain required

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah everyone does that..me too.bt the kid wanted a method...i know no one in the world would not use derivatives for this..even the kid will start using em after a couple of months

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ab question yeh hai ki jo ax aur bx hum multiply aur divide karte hain woh idhar kya kar rahen hai???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tujhe pata hai sinx / x is 1 when x tends to zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i k now dat is it a rule or smthing??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its the first rule you learn in limits

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sinx / x =1 and tanx / x is 1 when x tends to zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now if you have sin kx /x with x tending to zero and k any integer, whts the limit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin kx / x with x tending to zero??answer kya hai?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply and divide by k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah its k sorry yaar!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in the same way u treat ur question as two different limits and then take their ratio...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but if we do dis we get \[\sin ax/ax * ax = 1*ax = ax\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but then u have bx below..cancel x..u get a/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i cancel (sin ax)/ax ka x???? to get a i don't think so!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0vaise u cant..but when uve got b in the denominator u can

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how and y can i do dat??? any spl reason behind it???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0abe...............sinax / ax / tanbx / bx x a/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it the same as sinax/tanbx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to evaluate sinax/tanbx u need to form sinax/ ax/tanbx/bx....to make the expression same uve got to multiply by a/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0luks like i got it the sin x / x = 1 wala way!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got ax / bx where i can cancel x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this tareeka ok!!!!!!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin ax / tan bx = sin(ax) x ax  ax  tan (bx) x bx  bx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the ax between the 2 xes for multiplying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0abe that x is multiply

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if so tab theek hai got it!!!!!!
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