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cherrilyn

  • 5 years ago

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  1. cherrilyn
    • 5 years ago
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    1/9 + 1/16 + 1/25 + 1/36 + ......... I know it has something to do with a square in the denominator..

  2. anonymous
    • 5 years ago
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    1/n^2 , from 3-infinity

  3. anonymous
    • 5 years ago
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    \[\sum_{1}^{\infty}1/(n+2)^{2}\]

  4. anonymous
    • 5 years ago
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    \[\sum_{n=3}^{\infty} \frac{1}{n^2} \]

  5. anonymous
    • 5 years ago
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    yeah

  6. cherrilyn
    • 5 years ago
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    which one?

  7. anonymous
    • 5 years ago
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    both are same

  8. cherrilyn
    • 5 years ago
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    oh okay thank you :)

  9. cherrilyn
    • 5 years ago
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    what about for 1 - 1/3 + 1/5 - 1/7 +.......

  10. anonymous
    • 5 years ago
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    \[\sum_{n=0}^{\infty} (-1)^n \frac{1}{2n+1}\]

  11. cherrilyn
    • 5 years ago
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    and 125/9 + 625/16 + 3,125/25 + 15,625/36 . I know the bottom is n^2 but what's the top?

  12. anonymous
    • 5 years ago
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    the top are factgorials im fairly sure

  13. anonymous
    • 5 years ago
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    5!, 6! etc

  14. anonymous
    • 5 years ago
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    \[\sum_{n=3}^{ \infty} \frac{ (n+2)!}{n^2} \]

  15. anonymous
    • 5 years ago
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    wait, thats not right :|

  16. anonymous
    • 5 years ago
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    yeah

  17. anonymous
    • 5 years ago
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    its multiples of 5 on the top

  18. anonymous
    • 5 years ago
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    its powers of 5

  19. anonymous
    • 5 years ago
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    5^n / n^2

  20. anonymous
    • 5 years ago
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    thats it

  21. anonymous
    • 5 years ago
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    n=3 to infinity

  22. anonymous
    • 5 years ago
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    \[\sum_{n=3}^{\infty} 5^n \frac{5^2}{n^2} \]

  23. anonymous
    • 5 years ago
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    \[\sum_{n=3}^{\infty} \frac{5^{n+2}}{n^2}\]

  24. anonymous
    • 5 years ago
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    ur wrong mate

  25. anonymous
    • 5 years ago
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    if it starts from 3 then its 5^n

  26. anonymous
    • 5 years ago
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    no, thats not it :|

  27. anonymous
    • 5 years ago
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    yeh whatever

  28. cherrilyn
    • 5 years ago
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    ?

  29. anonymous
    • 5 years ago
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    \[\sum_{n=3}^{\infty}5^{n}/n ^{2}\]

  30. anonymous
    • 5 years ago
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    thats ur answer

  31. cherrilyn
    • 5 years ago
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    you're right ! Thanks :D Saved me

  32. anonymous
    • 5 years ago
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    no prob...

  33. anonymous
    • 5 years ago
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    hey could you look at myt problem pleaseeee

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