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anonymous

  • 5 years ago

A line passes through the points (-6, 3) and (x2, y2), and has a slope of 5/10. If point (x2, y2) is located in quadrant I, find x2. 4 -12 -7 -5

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  1. anonymous
    • 5 years ago
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    any ideas

  2. anonymous
    • 5 years ago
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    theres one piece of info missing

  3. anonymous
    • 5 years ago
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    2y - 6 = x+6 x2 = 2y2 -12

  4. anonymous
    • 5 years ago
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    this is all the problem says

  5. anonymous
    • 5 years ago
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    u need the value of y2

  6. anonymous
    • 5 years ago
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    the answer was 4 i went ahead and guessed

  7. anonymous
    • 5 years ago
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    guessing wont do u good...in the long term

  8. anonymous
    • 5 years ago
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    ive been n childrens hospital. I have missed all the explaining and my teacher exspects me to know it all. and its harder then she thinks.

  9. anonymous
    • 5 years ago
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    no prob..dont worry...were to help

  10. anonymous
    • 5 years ago
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    Thanks

  11. anonymous
    • 5 years ago
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    its obvious it had to be 4 lols , its the only positive answer, and for the point to be in the first quadrant then x must be positive

  12. anonymous
    • 5 years ago
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    oh that way..lol

  13. anonymous
    • 5 years ago
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    lol. How can they ask such questions? :D Neways good luck jessmaynard!

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spraguer (Moderator)
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