anonymous
  • anonymous
A line passes through the points (-6, 3) and (x2, y2), and has a slope of 5/10. If point (x2, y2) is located in quadrant I, find x2. 4 -12 -7 -5
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
any ideas
anonymous
  • anonymous
theres one piece of info missing
anonymous
  • anonymous
2y - 6 = x+6 x2 = 2y2 -12

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anonymous
  • anonymous
this is all the problem says
anonymous
  • anonymous
u need the value of y2
anonymous
  • anonymous
the answer was 4 i went ahead and guessed
anonymous
  • anonymous
guessing wont do u good...in the long term
anonymous
  • anonymous
ive been n childrens hospital. I have missed all the explaining and my teacher exspects me to know it all. and its harder then she thinks.
anonymous
  • anonymous
no prob..dont worry...were to help
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
its obvious it had to be 4 lols , its the only positive answer, and for the point to be in the first quadrant then x must be positive
anonymous
  • anonymous
oh that way..lol
anonymous
  • anonymous
lol. How can they ask such questions? :D Neways good luck jessmaynard!

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