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anonymous

  • 5 years ago

trains e and w leave the same city at the same time train e travels due north at 5 miles per hour slower than train w which is traveling due east. after two hours, they are 150 miles apart. find the speed of each train to the nearest whole #

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  1. anonymous
    • 5 years ago
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    please help me i need this answer badly!!

  2. anonymous
    • 5 years ago
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    looks relatively easy

  3. anonymous
    • 5 years ago
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    distance = rate x time

  4. anonymous
    • 5 years ago
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    let the speed of "train e" be x

  5. anonymous
    • 5 years ago
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    now we know the speed of train w is ( x+5)

  6. anonymous
    • 5 years ago
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    After two hours , train e has travelled (2x) miles ( because the time is 2hrs , and its rate is x miles/hr )

  7. anonymous
    • 5 years ago
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    similarly , after two hours , train w has travelled 2(x+5) miles

  8. anonymous
    • 5 years ago
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    now, one is travelling north, the other east, ie they are at right angle to one another , the distance between them represent the hypotenuse of a right angle triangle, which can be found by phytagorus

  9. anonymous
    • 5 years ago
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    so [ 2x}^2 + [ 2(x+5)]^2 = 150^2

  10. anonymous
    • 5 years ago
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    ^ from pythagorus

  11. anonymous
    • 5 years ago
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    then solve that ,

  12. anonymous
    • 5 years ago
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    you get solutions x=-64.5 and x= 57.85

  13. anonymous
    • 5 years ago
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    take the positive case, because we are dealing with speed

  14. anonymous
    • 5 years ago
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    thanks so much for all your help you saved my life- that totally makes sense!

  15. anonymous
    • 5 years ago
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    therefore speed train e is 57.85mph , and speed of traian w is 62.85mph ( ie x+5)

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