anonymous
  • anonymous
trains e and w leave the same city at the same time train e travels due north at 5 miles per hour slower than train w which is traveling due east. after two hours, they are 150 miles apart. find the speed of each train to the nearest whole #
Mathematics
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anonymous
  • anonymous
trains e and w leave the same city at the same time train e travels due north at 5 miles per hour slower than train w which is traveling due east. after two hours, they are 150 miles apart. find the speed of each train to the nearest whole #
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
please help me i need this answer badly!!
anonymous
  • anonymous
looks relatively easy
anonymous
  • anonymous
distance = rate x time

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anonymous
  • anonymous
let the speed of "train e" be x
anonymous
  • anonymous
now we know the speed of train w is ( x+5)
anonymous
  • anonymous
After two hours , train e has travelled (2x) miles ( because the time is 2hrs , and its rate is x miles/hr )
anonymous
  • anonymous
similarly , after two hours , train w has travelled 2(x+5) miles
anonymous
  • anonymous
now, one is travelling north, the other east, ie they are at right angle to one another , the distance between them represent the hypotenuse of a right angle triangle, which can be found by phytagorus
anonymous
  • anonymous
so [ 2x}^2 + [ 2(x+5)]^2 = 150^2
anonymous
  • anonymous
^ from pythagorus
anonymous
  • anonymous
then solve that ,
anonymous
  • anonymous
you get solutions x=-64.5 and x= 57.85
anonymous
  • anonymous
take the positive case, because we are dealing with speed
anonymous
  • anonymous
thanks so much for all your help you saved my life- that totally makes sense!
anonymous
  • anonymous
therefore speed train e is 57.85mph , and speed of traian w is 62.85mph ( ie x+5)

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