trains e and w leave the same city at the same time train e travels due north at 5 miles per hour slower than train w which is traveling due east. after two hours, they are 150 miles apart. find the speed of each train to the nearest whole #

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- anonymous

please help me i need this answer badly!!

- anonymous

looks relatively easy

- anonymous

distance = rate x time

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## More answers

- anonymous

let the speed of "train e" be x

- anonymous

now we know the speed of train w is ( x+5)

- anonymous

After two hours , train e has travelled (2x) miles ( because the time is 2hrs , and its rate is x miles/hr )

- anonymous

similarly , after two hours , train w has travelled 2(x+5) miles

- anonymous

now, one is travelling north, the other east, ie they are at right angle to one another , the distance between them represent the hypotenuse of a right angle triangle, which can be found by phytagorus

- anonymous

so [ 2x}^2 + [ 2(x+5)]^2 = 150^2

- anonymous

^ from pythagorus

- anonymous

then solve that ,

- anonymous

you get solutions x=-64.5 and x= 57.85

- anonymous

take the positive case, because we are dealing with speed

- anonymous

thanks so much for all your help you saved my life- that totally makes sense!

- anonymous

therefore speed train e is 57.85mph , and speed of traian w is 62.85mph ( ie x+5)

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