anonymous
  • anonymous
A vertical parabola has vertex (4,1) and Y intercept 5. What are its X intercepts?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
y= A(x-4)^2 + 1 is the general form of such a parabola
anonymous
  • anonymous
we know that when x=0, y= 5
anonymous
  • anonymous
so we can find A

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anonymous
  • anonymous
5 = 16A +1 A= (1/4)
anonymous
  • anonymous
so y= (1/4) (x-4)^2 + 1 x intercepts, set y=0
anonymous
  • anonymous
(x-4)^2 = -4 , this has no solution! , no x intercepts
anonymous
  • anonymous
Thank you
anonymous
  • anonymous
how did you get -4?

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