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anonymous
 5 years ago
csc h/ (tan h + cot h). Express in terms of sin h and cos h and simplify.
anonymous
 5 years ago
csc h/ (tan h + cot h). Express in terms of sin h and cos h and simplify.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hyperbolics behave the exact same as normal trig functions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0csc h = 1/sin h tan h = sin h /cos h cot h = cos h/ sin h = (1/sin h)/(sin/cos+cos/sin) =(1/sin)/(sin^2 + cos^2 / sin cos) =(1/sin)/(1/sin cos) =cos h//
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