anonymous 5 years ago tan²θ-√3tanθ=0. find solutions in the interval [0,360°). Round to the nearest ten minutes. Help!

1. anonymous

$tan^2(\theta)-\sqrt{3}tan(\theta)=0$ $tan(\theta)(tan(\theta)-\sqrt{3})=0$ $tan(\theta)=0$or $tan(\theta)=\sqrt{3}$

2. anonymous

of course you still have to solve for $\theta$

3. anonymous

$tan(\theta)=0$ $\theta=0$

4. anonymous

$tan(\theta)=\sqrt{3}$ $\theta=\frac{\pi}{3}$ or $\theta=\frac{4\pi}{3}$ of you ar working in degrees instead of radians it would be 60 and 240