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anonymous

  • 5 years ago

is Sin(A)=-sqrt(7)/4 and CosB=-sqrt(3)/3, find the value of Sin(A-B). Can you help me please ...

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  1. anonymous
    • 5 years ago
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    sinn(a-b)= sina* cos b - cosa* sinb

  2. anonymous
    • 5 years ago
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    but I dont have cos(A). How do I do

  3. anonymous
    • 5 years ago
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    tht mean we wanna cos A by sina^2+cosa^2=1 cos a = 1- (7/16) =3/4 & sin b by the same way = sqrt(6)/3

  4. anonymous
    • 5 years ago
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    ok now sin (a-b)= -sqrt7/4 * -sqrt(3)/3 - 3/4 * sqrt(6)/3 =sqrt (21)/12 - 3sqrt(6)/12 = \[\sqrt{}\]

  5. anonymous
    • 5 years ago
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    =(sqrt (7) -3 / 4*sqrt(3) ) is it clear??

  6. anonymous
    • 5 years ago
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    let me check it out

  7. anonymous
    • 5 years ago
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    ok take ur time hope i can help u

  8. anonymous
    • 5 years ago
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    yes sure. Youre helping me a lot

  9. anonymous
    • 5 years ago
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    Got it. Thanks It is very clear my friend

  10. anonymous
    • 5 years ago
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    ok , may allah bless u

  11. anonymous
    • 5 years ago
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    :)

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spraguer (Moderator)
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