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anonymous
 5 years ago
A customer purchased items costing $360 with a national credit card that charges 1.5% interest per month compounded monthly.
a. Write a recurrence relation and initial conditions for bn, the balance after n months if no further charges occur and the minimum monthly payment of $25 is made.
b. Find a general solution of the recurrence relation and the solution for this discrete dynamical system.
c. Give the value of the account after 12 months, i.e., b(12).
anonymous
 5 years ago
A customer purchased items costing $360 with a national credit card that charges 1.5% interest per month compounded monthly. a. Write a recurrence relation and initial conditions for bn, the balance after n months if no further charges occur and the minimum monthly payment of $25 is made. b. Find a general solution of the recurrence relation and the solution for this discrete dynamical system. c. Give the value of the account after 12 months, i.e., b(12).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have some it...just need some extra guidance

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[b_{n}=1.015b_{n1}  25 for n >0\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1B{0} = 360 right? since its debt?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would think it is just 360 applying debt as initial amount

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we can either look at it as the balance approaching zero from the left; or from the right i spose

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0used positive for amortized problem and got that part right

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1B{n+1} = B{n}(1.015)  25 looks right for a recurence equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have a chart so take from balance standpoint

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1B0 = 360 B1 = 360(1.015) 25 B2 = (360(1.01) 25)(1.015)25 B3 = (360(1.01) 25)(1.01)25)(1.015)25 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i really got no idea how to go from there ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the general solution is the homogenous?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1b0 = 360 b1 = 316.98 b2 = 295.16 b3 = 273.11 b4 = 250.84 b5 = 228.35 b6 = 205.64 b7 = 182.69 b8 = 159.52 b9 = 136.11 b10 = 112.47 b11 = 88.60 b12 = 64.49 these about right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have 360, 340.4, 320.5, 300.3, 279.80, 259, 237.9...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i always round up when working in money

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ack!!.. i did all that with 1.01 lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1there is a techniques refered to as variation of parameters that looks very close to this procedure... but i havent grasped it yet.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1in general; you are tryng to determine a constant of variation that will satisfy the homogenous part

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1B{n+1}  (1.015)B{n} = 0, or rather; B{n+1} = k* [1.015]B{n} and solve for k using the answers you found in the table

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have something...checking to see if it works
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