anonymous
  • anonymous
|-3|x|5|?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
15
anonymous
  • anonymous
Evaluate |7|
anonymous
  • anonymous
7

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More answers

anonymous
  • anonymous
|-13| ?
anonymous
  • anonymous
13
anonymous
  • anonymous
Select the smaller number in the given pair of numbers. |-10|, -1
anonymous
  • anonymous
-1
anonymous
  • anonymous
If we multiply the absolute values of -9 and 4, we get 36. True False
anonymous
  • anonymous
True
anonymous
  • anonymous
Evaluate. -7 - |-5 + 2|
anonymous
  • anonymous
Any more?
anonymous
  • anonymous
-10
anonymous
  • anonymous
Any more?
anonymous
  • anonymous
(-47) + (-74)
anonymous
  • anonymous
Is it (-47) + (-74) or |-47| + |-74|
anonymous
  • anonymous
the first one and whats the difference?
anonymous
  • anonymous
The answer for the first one is -121 and second one is +121
anonymous
  • anonymous
why are they two different answers? i thought they meant the same thing?
anonymous
  • anonymous
14 + ( )=0?
anonymous
  • anonymous
That would be a very long answer. Well, in short I can say, |x| means absolute value of x which means you only consider the +ve value of x, and the other one is simple addition
anonymous
  • anonymous
-14
anonymous
  • anonymous
ohh okay. -9 + 15 ?
anonymous
  • anonymous
You are getting your homework done by me
anonymous
  • anonymous
yea
anonymous
  • anonymous
Sorry, I can't help you cheat
anonymous
  • anonymous
However, I can do this if you pay for it
anonymous
  • anonymous
I mean if you allow me to tutor you
anonymous
  • anonymous
its a study guide not homework i work online and im looking up answers so i can study for my final exam
anonymous
  • anonymous
Do you need a tutor?
anonymous
  • anonymous
no not really i just need help on my study guide thats all
anonymous
  • anonymous
Please post your questions, and find some one else. I am a bit busy now.
anonymous
  • anonymous
okay thanks for helping me though :)

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