anonymous
  • anonymous
Actually, I stand corrected with my question. it is how does cos(-5pi/3)= -square root of 2/2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
its proved usually by drawing the angle inside the unit circle
anonymous
  • anonymous
i saw that unit circle and closed the trig book in fear and ran the other way!!! Do yo have to use the unit circle? If so, how does one read it? Btw, hello again from Illinois. Back for more torture, huh? ; )
amistre64
  • amistre64
you can use a triangle as well, bu the unit scircle is a better fit; im drawing one u p for you right now

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amistre64
  • amistre64
cos -5pi/3 is just about a full circle so; we can call it pi/3 = 60 cos(60) = 1/2 so i dont see a way to 'prove' it becasue its contradictory it first glance
anonymous
  • anonymous
yes you have to use the unit circle. put the 'reference triangle' inside it. or just use a cheat sheet. best one is here http://tutorial.math.lamar.edu/cheat_table.aspx
anonymous
  • anonymous
actually it does not!
amistre64
  • amistre64
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amistre64
  • amistre64
the cos of that angle = 1/2 regardless of any other measures
anonymous
  • anonymous
\[cos(-\frac{5\pi}{3})+=\frac{1}{2}\]
anonymous
  • anonymous
so looking at this unit circle. i see on there that 225 degrees, for example, is 5pi/4. but what if i wanted cos or sin? like in my original ? which asks cos(-5pi/4). does it not matter about the cos or sin? will the answer in square root always be the same?
anonymous
  • anonymous
\[= \]cos(-5pi/3) =cos(5pi/3) =\[cos( 2 \pi - 5\pi/3)\] \[=\cos(\pi / 3)\] = 1/2
amistre64
  • amistre64
cos is the x value of the angle dropped down to the x axis
amistre64
  • amistre64
sin is the y value
amistre64
  • amistre64
like this
amistre64
  • amistre64
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anonymous
  • anonymous
hey are you going to be around today? I am goiong to go investigate this unit circle and maybe I can get somewhere with it then! Thanks again, of course! Too bad you live so far away; i would pay a ton of money for your tutoring math abilities!
amistre64
  • amistre64
a ton eh ;) i should be around till about 5. cant say much for after that tho

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