## anonymous 5 years ago Simplify: (sin2a)/sina = (cos2a)/cosa

1. anonymous

2sin(a)cos(a)/sin(a) = cos(2a)/cos(a) 2cos(a) = cos(2a)/cos(a) $2\cos^2(a) = \cos(2a)$ $2\cos^2(a) = \cos^2(a) - \sin^2(a)$ $\cos^2(a) = -\sin^2(a)$ 1 = 0 No solution!

2. anonymous

I get now! I think I'm over thinking the question. Thank you!