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anonymous
 5 years ago
Find an equation of the following lines.
The line through (0,0, 1) parallel to the yaxis.
I don't get why the answer is r(t)= <0, 0, 1> + t<0, 1, 0>
anonymous
 5 years ago
Find an equation of the following lines. The line through (0,0, 1) parallel to the yaxis. I don't get why the answer is r(t)= <0, 0, 1> + t<0, 1, 0>

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is parametric form of the line

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1parallel to omits the component its paralelling right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we can pick to point; or vectors that point to 2 points and create a line from them P(x,y,z) = (0,0,1) another point that is parallel to the y mean that the ys are the same right? for instance (0,0,0) and (0,6,0) i guess i had that backewards lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1same others, diff y then lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(0,0,1) and lets say (0,4,1) should be parallel to the y right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it draws out right then :) we need a vector from one point to the other now; <0,4,1> works good right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so do you mean that i can pick any point as long as y value stay the same and z value is 1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0m not getting u at all :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1well, the unit vector; tha thas the same direction but a magnitude of 1 would be: <0,1,1>

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1nah; the x and z are the same; the y can be any value

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1P(0,0,1) and Q(0,1,1) are in line and parallel to the y axis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can the answer be r(t) = <0, 0, 1> + t<0, any y value here, 1>?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1this is the view looking straight at the x axis; and y is to the left and right and z i up and down.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the only way a line can be parallel to the y axis is to have z and x remain constant between points

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes it can; but to make things simple; they use a "unit" vector

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1so its length is 1; and then any value fo y just makes it scalar

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the line is a point plus a vector right? r(t) = P(0,0,1) + t<0,1,1> where t is a scalar amount

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i missed that 0 at the end :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ahh i see it; the vector is saying tha tit doesnt change from x to z; just the y value lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<0,1,0> means that it never stears away from the original x and z values; it just heads down y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i see. I see it now. but where did they get the vector <0, 1, 0>?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1any vector pointing in the same direction will work; so they simply choose what is called a "UNIT" vector. It has the same direction; but its length is equal to "1"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its just a standard for notation really

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its the direction you want ; the length of the vector doesnt matter

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1as long as it aint a zero vecotr that is lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just to make sure I totally understand this concept. So if i write r(t) = <0,0,1 > + t<0, 4, 0>, i'm still correct right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much to help me understand it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thank you for letting me :) the more i help the more I learn myself lol
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