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anonymous
 5 years ago
how do you factor this equation? x^3+6x^2+12x+8 = 0
anonymous
 5 years ago
how do you factor this equation? x^3+6x^2+12x+8 = 0

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0with a ten foot pole ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0start by getting number that might work by factoring the last over the first 1,8,2,4  makes life a little easier 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since all the terms are + already we know there are no positive solutions to be had so lets go with  tests

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets try x = 2 2  1 6 12 8 0 2 8 8  1 4 4 0 < its a good one casue we got 0 i n the end

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x=2 is a solution; (x+2) (x^2+4x+4) the quad factors quite nicely as well to get: (x+2)(x+2)(x+2) = (x+2)^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why did you use 2? not 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also how did you get (x+2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or: (x^3+6x^2)+(12x+8)=0 x^2(x+6)+4(3x+2)=0 (x^2+4)(x+6)(3x+2)=0 x=6 x=2/3 x^2=4 \[x=\sqrt{4} = \pm 2\] then plug check to see which one solution, I think x=2 is solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for your medal

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the rule for wigns tells me that if all are + then there are no poistive roots to be had; so I went with the negative versions of my gene pool

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0rule for signs.... its like im having a stroke lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have to set factors equal to zero and solve...so much easier doing this stuff than my own...grrhhhh, lol!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the way amis do is call long division,you can do that way too ,but is hard to explant

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = sqrt(4) = 2 NOT +2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0not long division; close tho; synthetic division ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(4) = 2 2^2 = + sqrt(4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0got it lol i read it wrong

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now the question asked to factor it; not find roots right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x+2)^3 is the factored form then
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