anonymous
  • anonymous
how do you factor this equation? x^3+6x^2+12x+8 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
with a ten foot pole ?
amistre64
  • amistre64
start by getting number that might work by factoring the last over the first 1,8,2,4 ------ makes life a little easier 1
anonymous
  • anonymous
factor by grouping

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amistre64
  • amistre64
since all the terms are + already we know there are no positive solutions to be had so lets go with - tests
amistre64
  • amistre64
lets try x = -2 -2 | 1 6 12 8 0 -2 -8 -8 ----------- 1 4 4 0 <- its a good one casue we got 0 i n the end
amistre64
  • amistre64
x=-2 is a solution; (x+2) (x^2+4x+4) the quad factors quite nicely as well to get: (x+2)(x+2)(x+2) = (x+2)^3
anonymous
  • anonymous
why did you use -2? not 2
anonymous
  • anonymous
also how did you get (x+2)
anonymous
  • anonymous
or: (x^3+6x^2)+(12x+8)=0 x^2(x+6)+4(3x+2)=0 (x^2+4)(x+6)(3x+2)=0 x=-6 x=-2/3 x^2=4 \[x=\sqrt{4} = \pm 2\] then plug check to see which one solution, I think x=-2 is solution
anonymous
  • anonymous
Algebra I style : )
anonymous
  • anonymous
thank you for your medal
amistre64
  • amistre64
the rule for wigns tells me that if all are + then there are no poistive roots to be had; so I went with the negative versions of my gene pool
amistre64
  • amistre64
rule for signs.... its like im having a stroke lol
anonymous
  • anonymous
have to set factors equal to zero and solve...so much easier doing this stuff than my own...grrhhhh, lol!
anonymous
  • anonymous
the way amis do is call long division,you can do that way too ,but is hard to explant
amistre64
  • amistre64
x = sqrt(4) = 2 NOT +-2
amistre64
  • amistre64
not long division; close tho; synthetic division ;)
anonymous
  • anonymous
square= +-
amistre64
  • amistre64
sqrt(4) = 2 2^2 = +- sqrt(4)
amistre64
  • amistre64
got it lol i read it wrong
anonymous
  • anonymous
yes ,almos close
amistre64
  • amistre64
now the question asked to factor it; not find roots right?
amistre64
  • amistre64
(x+2)^3 is the factored form then

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