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anonymous

  • 5 years ago

What is the equation of an ellipse with foci at (-4, 0) and (-4, -6) and major axis of 10? I believe my answer is wrong so please help me :)

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  1. anonymous
    • 5 years ago
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    please help ! :)

  2. amistre64
    • 5 years ago
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    since the x values there are the same; we now it streches along a y axis parallel line

  3. amistre64
    • 5 years ago
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    half the distance between foci to find the distance to the center.. 0 - -6 = 6 6/2 = 3 the center is at (-4,-3) then

  4. amistre64
    • 5 years ago
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    i believe "major axis of 10" means the distance from tip to tip; so that leaves us with 5 from center to the outer vertex

  5. amistre64
    • 5 years ago
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    x^2 y^2 ---- + ---- = 1 s^2 L^2 L^2 = 5^2 = 25 x^2 y^2 ---- + ---- = 1 s^2 25 s^2 = Maj axis distance^2 - foci distance^2 s^2 = 5^2 - 3^2 s^2 = 25 - 9 = 16 ---------------------- x^2 y^2 ---- + ---- = 1 16 25 now when x = 0; y = +-5, and when y=0 x=+-4; but we have to put back over in its original spot; right now its at the origin

  6. amistre64
    • 5 years ago
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    (x+4)^2 (y+3)^2 -------- + -------- = 1 16 25

  7. amistre64
    • 5 years ago
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    the 16 and 25 are backwards :)

  8. amistre64
    • 5 years ago
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    no they arent...y is the major; never mind that idiot in the back of my head :)

  9. dumbcow
    • 5 years ago
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    Here is a ref sheet for ellipses, hyperbolas that might help you

  10. amistre64
    • 5 years ago
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    wha!?! theres already stuff out for this ;)

  11. anonymous
    • 5 years ago
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    Thank you both so much! That all really helped me!! I appreciate all of the help :)

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