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anonymous

  • 5 years ago

Add. Simplify by removing factors of 1 28zx + z-7x ----- ----- z^2-49x^2 z+7x

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  1. anonymous
    • 5 years ago
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    What? :)

  2. anonymous
    • 5 years ago
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    Add. simplify by removing factors of 1

  3. anonymous
    • 5 years ago
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    step by step so i can make notes to do next one on my own plz

  4. myininaya
    • 5 years ago
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    \[\frac{28zx}{(z-7x)(z+7x)}+\frac{z-7x}{z+7x}\]

  5. myininaya
    • 5 years ago
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    i have to go but u need to find a common denominator

  6. anonymous
    • 5 years ago
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    i really need help someone plz

  7. anonymous
    • 5 years ago
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    i really need help someone plz

  8. anonymous
    • 5 years ago
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    Okay, I see the exercise in mathematical notation now, so I know what to do. :) Here is how it goes... 1) 28zx/(z-7x)(z+7x) (explanation: 28zx remains as is for now, but we have to focus on this part (z-7x)(z+7x) so follow up close with what I'm doing here: the first part (z - 7x)...z and -7x multiplies with the first and second of the second parenthesis like so: (z-7x)(z+7x) = z^2 + 7zx - 7zx - 49x^2 and now you keep solving z^2 - 49x^2, and now you have 28zx/z^2-49x^2 + z-7x/z+7x and now you kind of have to apply what you learned about adding fractions...) You multiply them in cross... 28zx * z + 7x and z^2 - 49x^2... and see what you get.

  9. anonymous
    • 5 years ago
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    @tina-ann: Did I help any? :-)

  10. anonymous
    • 5 years ago
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    yes but could you show ur work

  11. anonymous
    • 5 years ago
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    Please forget everything I wrote earlier. :-) I'm not so sure at the moment how I can do it, but I'll post as soon as I get it solved.

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