Add. Simplify by removing factors of 1 28zx + z-7x ----- ----- z^2-49x^2 z+7x

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Add. Simplify by removing factors of 1 28zx + z-7x ----- ----- z^2-49x^2 z+7x

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What? :)
Add. simplify by removing factors of 1
step by step so i can make notes to do next one on my own plz

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\[\frac{28zx}{(z-7x)(z+7x)}+\frac{z-7x}{z+7x}\]
i have to go but u need to find a common denominator
i really need help someone plz
i really need help someone plz
Okay, I see the exercise in mathematical notation now, so I know what to do. :) Here is how it goes... 1) 28zx/(z-7x)(z+7x) (explanation: 28zx remains as is for now, but we have to focus on this part (z-7x)(z+7x) so follow up close with what I'm doing here: the first part (z - 7x)...z and -7x multiplies with the first and second of the second parenthesis like so: (z-7x)(z+7x) = z^2 + 7zx - 7zx - 49x^2 and now you keep solving z^2 - 49x^2, and now you have 28zx/z^2-49x^2 + z-7x/z+7x and now you kind of have to apply what you learned about adding fractions...) You multiply them in cross... 28zx * z + 7x and z^2 - 49x^2... and see what you get.
@tina-ann: Did I help any? :-)
yes but could you show ur work
Please forget everything I wrote earlier. :-) I'm not so sure at the moment how I can do it, but I'll post as soon as I get it solved.

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