anonymous 5 years ago How do you factor 3x^2+2x-8

1. anonymous

You can always solve these kind of problems by solving the above equation =0 You can do that by this formula: $(-b \pm \sqrt{b ^{2}-4ac})/2$ where ax^2+bx+c=0 So here: a=3 b=2 c=-8

2. anonymous

/2a

3. anonymous

so it is -2+-sqrt100/6 that is -2 and 4/3 So the factor is 3(x+2)(x-4/3)

4. anonymous

Thank you

5. anonymous

No problem

6. gw2011