Nancy can you help me
Radium decreases at the rate of 0.0428 percent per year.
a. What is its half-life? (A half-life of a radioactive substance is defined to be the time needed for half of the material to dissipate.
b. Write a recurrence relation to describe the decay of radium, where rn is the amount of radium remaining after n years.

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Read carefully...
http://books.google.com/books?id=Lq3Z34tj0XEC&pg=PA381&lpg=PA381&dq=Radium+decreases+at+the+rate+of+0.0428+percent+per+year.&source=bl&ots=gyde8oUJOg&sig=jAlWjNedjAw_CDmNHLzu_vX5VeY&hl=en&ei=VsDNTeCWCMe2twe94dT9DQ&sa=X&oi=book_result&ct=result&resnum=4&ved=0CCkQ6AEwAw#v=onepage&q&f=false

- anonymous

THANKS!

- anonymous

;)

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## More answers

- anonymous

y = Ae^(-kt)

- anonymous

general formula for exponential decay

- anonymous

A/2=A(0.000428)^x
1/2=(0.000428)^x
find x

- anonymous

* correction
A/2=A(1-0.000428)^x

- anonymous

\[1/2=(1-0.000428)^x\]

- anonymous

\[\log _{0.999572}(.5)\]

- anonymous

ok

- anonymous

that's half life

- anonymous

so how does translate to what I need for b

- anonymous

\[r_n=r_{n-1}(0.999572)\]

- anonymous

are you electrical engineer or student?

- anonymous

student this is module for 1 credit and I'm struggling!

- anonymous

I was asking elecengineer

- anonymous

sorry

- anonymous

np

- anonymous

by the way, did you figure out that credit card problem?

- anonymous

Suppose that one started out with 2 grams of radium. Find a solution for the discrete dynamical system illustrating this process and give the value for r(100), the amount remaining after 100 years.

- anonymous

yes

- anonymous

Okay,
we can use above formula
=2(1-0.000428)^100

- anonymous

approximately 1.92

- anonymous

that make sense because its half life in 1619 years so in 100 years there is not much difference

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