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anonymous

  • 5 years ago

Nancy can you help me Radium decreases at the rate of 0.0428 percent per year. a. What is its half-life? (A half-life of a radioactive substance is defined to be the time needed for half of the material to dissipate. b. Write a recurrence relation to describe the decay of radium, where rn is the amount of radium remaining after n years.

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  1. anonymous
    • 5 years ago
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    THANKS!

  2. anonymous
    • 5 years ago
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    ;)

  3. anonymous
    • 5 years ago
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    y = Ae^(-kt)

  4. anonymous
    • 5 years ago
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    general formula for exponential decay

  5. anonymous
    • 5 years ago
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    A/2=A(0.000428)^x 1/2=(0.000428)^x find x

  6. anonymous
    • 5 years ago
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    * correction A/2=A(1-0.000428)^x

  7. anonymous
    • 5 years ago
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    \[1/2=(1-0.000428)^x\]

  8. anonymous
    • 5 years ago
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    \[\log _{0.999572}(.5)\]

  9. anonymous
    • 5 years ago
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    ok

  10. anonymous
    • 5 years ago
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    that's half life

  11. anonymous
    • 5 years ago
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    so how does translate to what I need for b

  12. anonymous
    • 5 years ago
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    \[r_n=r_{n-1}(0.999572)\]

  13. anonymous
    • 5 years ago
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    are you electrical engineer or student?

  14. anonymous
    • 5 years ago
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    student this is module for 1 credit and I'm struggling!

  15. anonymous
    • 5 years ago
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    I was asking elecengineer

  16. anonymous
    • 5 years ago
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    sorry

  17. anonymous
    • 5 years ago
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    np

  18. anonymous
    • 5 years ago
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    by the way, did you figure out that credit card problem?

  19. anonymous
    • 5 years ago
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    Suppose that one started out with 2 grams of radium. Find a solution for the discrete dynamical system illustrating this process and give the value for r(100), the amount remaining after 100 years.

  20. anonymous
    • 5 years ago
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    yes

  21. anonymous
    • 5 years ago
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    Okay, we can use above formula =2(1-0.000428)^100

  22. anonymous
    • 5 years ago
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    approximately 1.92

  23. anonymous
    • 5 years ago
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    that make sense because its half life in 1619 years so in 100 years there is not much difference

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