Can some one please help me with Permutations and Combinatorics. The question is A farmer has 3 children and a herd of 27 cows. He gives 8 cows to his oldest child and 4 cows to his youngest child. Find the number of different ways the farmer can split up his herd.

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- anonymous

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- anonymous

27C8 x 19C4

- anonymous

how did you get that though im confused

- anonymous

the first child, picks 8 from the 27
then we have 19 left , then the second picks 4 from this 19
then the third child get whatevers left over ( ie they choose 15 out of the 15 remaining )
but 15C15 is one, so you just multiply by 1

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- anonymous

Thanks but i still dont get it lol

- anonymous

whats not to get :|

- anonymous

its actually one of the easiest combinations questions you will come across

- anonymous

cause im dumb when it comes to math

- anonymous

he gave us a take home quiz with 5questions and i cant even solve one of them thats sad lol

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