Can some one please help me with Permutations and Combinatorics. The question is A farmer has 3 children and a herd of 27 cows. He gives 8 cows to his oldest child and 4 cows to his youngest child. Find the number of different ways the farmer can split up his herd.
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27C8 x 19C4
how did you get that though im confused
the first child, picks 8 from the 27
then we have 19 left , then the second picks 4 from this 19
then the third child get whatevers left over ( ie they choose 15 out of the 15 remaining )
but 15C15 is one, so you just multiply by 1