anonymous
  • anonymous
Add. Simplify by removing factors of 1if possible 28zx + z-7x ----- ----- z^2-49x^2 z+7x I dont know how to do the exponents without this ^
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I think I might've solved it! :-) 28zx/2z+14x
anonymous
  • anonymous
But do you have the result somewhere to double check for me?
anonymous
  • anonymous
The way I did it is: 28zx/(z-7x)(z+7x) + z-7x/z+7x Explanation: (z-7x) with z-7x are reduced...you just cross them out and then you just add them together 28zx remains alone on the top si on the bottom we have z+7x + z+7x which equals 2z+14x so that's why I came up with the answer as being 28zx/2z+14x. It would've been good to know if you had the response somewhere at the end of the book so we can double check the answer.

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anonymous
  • anonymous
Nope, that's no the right answer. It can be done though..., that's all I know for now.
anonymous
  • anonymous
i dont its a question on my practice test
anonymous
  • anonymous
I'm still working on it! :)
radar
  • radar
28zx+1 -------- z+7x
anonymous
  • anonymous
It's 28zx+z^2+49x^2 :D
anonymous
  • anonymous
This is definitely the answer! :P I knew it can be done!
anonymous
  • anonymous
But it must be simplified some more though. :P
anonymous
  • anonymous
Just a second... :D
radar
  • radar
mowrey almost had it right to begin with. When you cancel don't forget the 1that is there when you cancel
anonymous
  • anonymous
Final result! z^2+14xz+49x^2
gw2011
  • gw2011
I get an answer of (z+7x)/(z-7x). Here is how I arrived at the answer: 28zx/(z^2-49x^2) + (z-7x)/(z+7x) Factor the bottom left term to get: 28zx/(z-7x)(z+7x) + (z-7x)/(z+7x) Now find a common denominator to get: [(28zx + (z-7x)(z-7x)]/(z-7x)(z+7x) (28zx+z^2-14zx+49x^2)/(z-7x)(z+7x) (z^2+14zx+49x^2)/(z-7x)(z+7x) Factor the top term to get: (z+7x)(z+7x)/(z-7x)(z+7x) = (z+7x)/(z-7x)
anonymous
  • anonymous
Nah, it's still going! I have this (z^2+14xz+49x^2) / (z^2-49x^2)...
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
mowrey the same my answer
anonymous
  • anonymous
wait almost ,
anonymous
  • anonymous
Yes, and it goes down to your answer! :) (z+7x)/(z-7x)
anonymous
  • anonymous
Very good radar! You're the man!
anonymous
  • anonymous
I mean gw2011...sorry! :D
anonymous
  • anonymous
Man, what an exercise...! :D I've been struggling with it since she posted it the first time...several hours ago!
radar
  • radar
28zx z-7x ------- + ------ z^2-49x^2 z+ 7x 28zx z-7x ---------- + -------- (z+7x)(z-7x) z+x 28zx (z-7x)(z-7x) -------- + ----------- (z+7x)(z-7x) (z+7x)(z-7x) 28zx + z^2-14zx+49x^2 ------------------------------ (z+7x)(z-7x) z^2+14zx+49x^2 ---------------- (z+7x)(z-7x) (z+7x)(z+7x) ------------ (z+7x)(z-7x) z+7x ------ z-7x
radar
  • radar
I started with the same mistake "cancelling" when I shouldn't lol
radar
  • radar
gw2011 did it right.
anonymous
  • anonymous
Yes, he was the first to post the result! :D

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