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anonymous

  • 5 years ago

Add. Simplify by removing factors of 1if possible 28zx + z-7x ----- ----- z^2-49x^2 z+7x I dont know how to do the exponents without this ^

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  1. anonymous
    • 5 years ago
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    I think I might've solved it! :-) 28zx/2z+14x

  2. anonymous
    • 5 years ago
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    But do you have the result somewhere to double check for me?

  3. anonymous
    • 5 years ago
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    The way I did it is: 28zx/(z-7x)(z+7x) + z-7x/z+7x Explanation: (z-7x) with z-7x are reduced...you just cross them out and then you just add them together 28zx remains alone on the top si on the bottom we have z+7x + z+7x which equals 2z+14x so that's why I came up with the answer as being 28zx/2z+14x. It would've been good to know if you had the response somewhere at the end of the book so we can double check the answer.

  4. anonymous
    • 5 years ago
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    Nope, that's no the right answer. It can be done though..., that's all I know for now.

  5. anonymous
    • 5 years ago
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    i dont its a question on my practice test

  6. anonymous
    • 5 years ago
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    I'm still working on it! :)

  7. radar
    • 5 years ago
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    28zx+1 -------- z+7x

  8. anonymous
    • 5 years ago
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    It's 28zx+z^2+49x^2 :D

  9. anonymous
    • 5 years ago
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    This is definitely the answer! :P I knew it can be done!

  10. anonymous
    • 5 years ago
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    But it must be simplified some more though. :P

  11. anonymous
    • 5 years ago
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    Just a second... :D

  12. radar
    • 5 years ago
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    mowrey almost had it right to begin with. When you cancel don't forget the 1that is there when you cancel

  13. anonymous
    • 5 years ago
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    Final result! z^2+14xz+49x^2

  14. gw2011
    • 5 years ago
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    I get an answer of (z+7x)/(z-7x). Here is how I arrived at the answer: 28zx/(z^2-49x^2) + (z-7x)/(z+7x) Factor the bottom left term to get: 28zx/(z-7x)(z+7x) + (z-7x)/(z+7x) Now find a common denominator to get: [(28zx + (z-7x)(z-7x)]/(z-7x)(z+7x) (28zx+z^2-14zx+49x^2)/(z-7x)(z+7x) (z^2+14zx+49x^2)/(z-7x)(z+7x) Factor the top term to get: (z+7x)(z+7x)/(z-7x)(z+7x) = (z+7x)/(z-7x)

  15. anonymous
    • 5 years ago
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    Nah, it's still going! I have this (z^2+14xz+49x^2) / (z^2-49x^2)...

  16. anonymous
    • 5 years ago
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  17. anonymous
    • 5 years ago
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    mowrey the same my answer

  18. anonymous
    • 5 years ago
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    wait almost ,

  19. anonymous
    • 5 years ago
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    Yes, and it goes down to your answer! :) (z+7x)/(z-7x)

  20. anonymous
    • 5 years ago
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    Very good radar! You're the man!

  21. anonymous
    • 5 years ago
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    I mean gw2011...sorry! :D

  22. anonymous
    • 5 years ago
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    Man, what an exercise...! :D I've been struggling with it since she posted it the first time...several hours ago!

  23. radar
    • 5 years ago
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    28zx z-7x ------- + ------ z^2-49x^2 z+ 7x 28zx z-7x ---------- + -------- (z+7x)(z-7x) z+x 28zx (z-7x)(z-7x) -------- + ----------- (z+7x)(z-7x) (z+7x)(z-7x) 28zx + z^2-14zx+49x^2 ------------------------------ (z+7x)(z-7x) z^2+14zx+49x^2 ---------------- (z+7x)(z-7x) (z+7x)(z+7x) ------------ (z+7x)(z-7x) z+7x ------ z-7x

  24. radar
    • 5 years ago
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    I started with the same mistake "cancelling" when I shouldn't lol

  25. radar
    • 5 years ago
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    gw2011 did it right.

  26. anonymous
    • 5 years ago
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    Yes, he was the first to post the result! :D

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