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- anonymous

a = ? , b = ?

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- anonymous

a = ? , b = ?

- chestercat

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- anonymous

- anonymous

4/8 = a/b for the first eqn yes?

- anonymous

now you need a another eqn

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- anonymous

well , we can find the distance between (12,0) and (3,9) , and that distance should be equal to a+b

- anonymous

distance between the points = sqrt [ ( 12-3)^2 + (0-9)^2 ] = sqrt [ 9^2 + 9^2]
= sqrt( 2 x 9^2) = 9sqrt(2)

- anonymous

so a/b = (1/2) --> ie b =2a , and a+b = 9sqrt(2)
2 eqns, two unknowns, pretty easy to solve yes?

- anonymous

I assume you can solve them, ill leave it to you

- anonymous

i'm alittle confuse right now

- anonymous

it doesnt help if u dont say what it is you are confused about.
nevertheless , this questionn is pretty similar to the other ones you put up ( though it is a bit harder ).
The first eqn came from ratios of intersections of parallel lines

- anonymous

then we needed to find another eqn to relate a and b , because you need two eqns to solve two unknowns , and we obverse from the picture that a+b was a distance between two points

- anonymous

(h/H)2 = 9/25; Volume of large prism/Volume of small prism= (h/H)3

- anonymous

:S, dont really undertand what u want

- anonymous

my bad n it not that one up there
a + b = sq root of (12-3)2 + (0-9)2. Once you have solved for a + b, then 4/12 = a/a+b .

- anonymous

I guess that would have been another way to get the second eqn

- anonymous

got is 12.7292206

- anonymous

are u still there?

- anonymous

what?
the answers to the question are
a=3sqrt(2)
b= 6sqrt(2)

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