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anonymous

  • 5 years ago

how to determine if a given number is a perfect square or not?

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  1. anonymous
    • 5 years ago
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    Find the square root, and see if its an integer or not. If its an integer then the number was a perfect sqare

  2. anonymous
    • 5 years ago
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    any other short cuts?

  3. anonymous
    • 5 years ago
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    Depends on the case you are dealing with

  4. anonymous
    • 5 years ago
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    any example?

  5. anonymous
    • 5 years ago
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    You give me examples and I will do it for you, I don't know your level. If I say If 8n+1 is a perfect square what can you say about n then this question can go above your level. So you need to tell me what you r level is

  6. anonymous
    • 5 years ago
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    1,3,6,10,15,21,28,36,45 and so on. couldn't reply yesterday b coz of connection failure

  7. anonymous
    • 5 years ago
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    ha ha. No not that. The answer is "2n can't be a perfect square" or "\[\sqrt (8n+1)\]" is always odd.

  8. anonymous
    • 5 years ago
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    i don't get u

  9. anonymous
    • 5 years ago
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    Thats why I told you to provide me problems, rather than having problems from me.

  10. anonymous
    • 5 years ago
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    8(1)+1=9 8(3)+1=25 8(6)+1=49 8(10)+1=81 all of them are perfect squares. what then?

  11. anonymous
    • 5 years ago
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    The question was, what is the property of n, when 8n+1 is a perfect square. What you are doing is just putting values and seeing if they are satisfying the relation I gave you. But thats not the problem. The problem is to prove the two answer statement I gave you. i.e. "2n can't be a perfect square" or "(√8n+1) is always odd." I didn't get them by guess work, I proved them, and that is what is expected.

  12. anonymous
    • 5 years ago
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    oh ok. thanks

  13. anonymous
    • 5 years ago
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    thanks again then:)

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