anonymous
  • anonymous
how to determine if a given number is a perfect square or not?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Find the square root, and see if its an integer or not. If its an integer then the number was a perfect sqare
anonymous
  • anonymous
any other short cuts?
anonymous
  • anonymous
Depends on the case you are dealing with

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anonymous
  • anonymous
any example?
anonymous
  • anonymous
You give me examples and I will do it for you, I don't know your level. If I say If 8n+1 is a perfect square what can you say about n then this question can go above your level. So you need to tell me what you r level is
anonymous
  • anonymous
1,3,6,10,15,21,28,36,45 and so on. couldn't reply yesterday b coz of connection failure
anonymous
  • anonymous
ha ha. No not that. The answer is "2n can't be a perfect square" or "\[\sqrt (8n+1)\]" is always odd.
anonymous
  • anonymous
i don't get u
anonymous
  • anonymous
Thats why I told you to provide me problems, rather than having problems from me.
anonymous
  • anonymous
8(1)+1=9 8(3)+1=25 8(6)+1=49 8(10)+1=81 all of them are perfect squares. what then?
anonymous
  • anonymous
The question was, what is the property of n, when 8n+1 is a perfect square. What you are doing is just putting values and seeing if they are satisfying the relation I gave you. But thats not the problem. The problem is to prove the two answer statement I gave you. i.e. "2n can't be a perfect square" or "(√8n+1) is always odd." I didn't get them by guess work, I proved them, and that is what is expected.
anonymous
  • anonymous
oh ok. thanks
anonymous
  • anonymous
thanks again then:)

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