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anonymous
 5 years ago
If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? Use the hangtime function V=48T^2
anonymous
 5 years ago
If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? Use the hangtime function V=48T^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does V stand for in the formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think vertical? Not sure..this week in class I have been very confused....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it's the vertical distance, then substitute it , 35=48T^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[35=48T^2\]\[T=\sqrt{35/48}\] T=.8539 seconds

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep, that may be right. but what if V turns out to be VELOCITY, though not so likely?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is for vertical leaps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then .8539 is the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then .8539 is the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just tried it and it kicked back saying it was wrong as well...cause my answer was close to that as well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the V means vertical leaps in minutes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need this solved...I really am just checking the answers I got wrong to see where I went wrong
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