1. anonymous

ok

2. anonymous

$\sqrt{16r^7s^5}+7r^2\sqrt{r^3 s^5}-7rs \sqrt{r^5s^3}$ you mean this?

3. anonymous

im guessing each are different?

4. anonymous

need clarification

5. anonymous

yes i meant that \. I didn't know how to to type it

6. anonymous

o.k, so first look at the radical sign

7. anonymous

you want to grab pairs

8. anonymous

so you can rewrite it as $\sqrt{16r^6rs^4s}$

9. anonymous

for the first term

10. anonymous

so just take each individual root

11. anonymous

$\sqrt{16}=4$

12. anonymous

one way to look at the r^6 is to divide the exponent by 2

13. anonymous

you will do the same to the s^4

14. anonymous

Ive done all of this correct, but i keep getting the wrong answer

15. anonymous

we need pairs so we will have r and s inside the radical.

16. anonymous

o.k, what are u getting?

17. anonymous

What did you get?

18. anonymous

???

19. anonymous

im getting $4r^3s^2\sqrt{rs}$