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anonymous
 5 years ago
Simplify: Radical 16r ^7 s^5+ 7r^2 Radical r^3s^57rs radical r^5s^3
anonymous
 5 years ago
Simplify: Radical 16r ^7 s^5+ 7r^2 Radical r^3s^57rs radical r^5s^3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{16r^7s^5}+7r^2\sqrt{r^3 s^5}7rs \sqrt{r^5s^3}\] you mean this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im guessing each are different?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i meant that \. I didn't know how to to type it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o.k, so first look at the radical sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to grab pairs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you can rewrite it as \[\sqrt{16r^6rs^4s}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so just take each individual root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0one way to look at the r^6 is to divide the exponent by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you will do the same to the s^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ive done all of this correct, but i keep getting the wrong answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we need pairs so we will have r and s inside the radical.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0o.k, what are u getting?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is you final answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im getting \[4r^3s^2\sqrt{rs}\]
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