anonymous
  • anonymous
Simplify: Radical 16r ^7 s^5+ 7r^2 Radical r^3s^5-7rs radical r^5s^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
ok
anonymous
  • anonymous
\[\sqrt{16r^7s^5}+7r^2\sqrt{r^3 s^5}-7rs \sqrt{r^5s^3}\] you mean this?
anonymous
  • anonymous
im guessing each are different?

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anonymous
  • anonymous
need clarification
anonymous
  • anonymous
yes i meant that \. I didn't know how to to type it
anonymous
  • anonymous
o.k, so first look at the radical sign
anonymous
  • anonymous
you want to grab pairs
anonymous
  • anonymous
so you can rewrite it as \[\sqrt{16r^6rs^4s}\]
anonymous
  • anonymous
for the first term
anonymous
  • anonymous
so just take each individual root
anonymous
  • anonymous
\[\sqrt{16}=4\]
anonymous
  • anonymous
one way to look at the r^6 is to divide the exponent by 2
anonymous
  • anonymous
you will do the same to the s^4
anonymous
  • anonymous
Ive done all of this correct, but i keep getting the wrong answer
anonymous
  • anonymous
we need pairs so we will have r and s inside the radical.
anonymous
  • anonymous
o.k, what are u getting?
anonymous
  • anonymous
What did you get?
anonymous
  • anonymous
???
anonymous
  • anonymous
what is you final answer?
anonymous
  • anonymous
im getting \[4r^3s^2\sqrt{rs}\]

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