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anonymous
 5 years ago
During the first part of a trip, a conoeist travels 34 miles at a certain speed. The conoeist travels 6 miles on the second part of the trip at a speed of 5mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip?
anonymous
 5 years ago
During the first part of a trip, a conoeist travels 34 miles at a certain speed. The conoeist travels 6 miles on the second part of the trip at a speed of 5mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh, its very similar to all questions asked one use pronumerals to represent unknowns

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let the first speed be x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then distance = rate x time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0time for first section of trip is T1 = 34/x now, the speed they travel for second part of trip is (x5) { 5mph slower} so time for second part = T2 = 6/ (x5) and we are told that the total trip = 3hrs so the sum of the times = 3hrs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{34}{x} + \frac{6}{x5} = 3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this gives 2 solutions x= 3.94 and x= 14.4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now, the answer cannot be x=3.94 , because if we try to determine the speed of the second part of the trip then we would get a negative value ( remember the speed for second trip was (x5)mph )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0therefore x=14.4mph is the speed for first section , and 9.4mph is the speed for the second section

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need to solve....well see what the heck I did wrong anyway..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then I have one more..if that is ok...then I will leave everyone alone...I hate that I get so confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0square both sides 9x + 67 = x^2 +10x +25 x^2 +x +2567 =0 x^2 + x 42=0 (x+7)(x6) =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=6, x=7 but check your solns

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=7 doesnt work, so x=6 is only soln

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so one more if you have time?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0might as well, shouldnt take long

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Write a quadratic equation in the variable x having the given numbers as solutions. The equation is standard form, ax^2+bx+c=0 \[\sqrt{3}, 6\sqrt{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x+\sqrt{3}) ( x6\sqrt{3}) =0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 6sqrt(3)x +sqrt(3)x 6sqrt(3)sqrt(3) =0 \[x^2  6\sqrt{3}x  18 =0 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2 5\sqrt{3}x 18 =0 \] thats it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you have a quadratic eqn with roots a and b , then the formula for that quadratic is (xa)(xb) =0
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